In which equation is y a nonlinear function of x

Colt1911 [192]

Answer: parabola

Explanation:

•Parabolic Trajectory:

In conclusion, projectiles travel with a parabolic trajectory due to the fact that the downward force of gravity accelerates them downward from their otherwise straight-line, gravity-free trajectory.

5 0

3 years ago

Para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al

padilas [110]

Answer:

Se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.

Explanation:

Dado que para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al vacío, y en el evaporador se elimina el agua necesaria para que el jugo salga con una concentración del 60% de peso de sólidos, si se introducen al proceso 1000 kg/h de jugo diluido, para calcular la cantidad de agua evaporada y de jugo concentrado saliente se debe realizar el siguiente cálculo;

1000 x 0.07 = 70

60 = 70

100 = X

100 x 70 / 60 = X

7000 / 60 = X

116.66 = X

Por lo tanto, se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.

4 0

3 years ago

Find the equivalent impedance Zeq seen by the source when Vs = 5 cos (2t) v, C = 2 F, R = 1 Ω and L = 1 H. (Give angles in degre

Lapatulllka [165]

Answer:

Explanation:

Find attach the solution

5 0

3 years ago

A car is moving at 68 miles per hour. The kinetic energy of that car is 5 × 10 5 J.How much energy does the same car have when i

Blababa [14]

Answer:

The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour

Explanation:

Given the data in the question;

Initial velocity v₁ = 68 miles per hour = 30.398 meter per seconds

let mass of the car be m

kinetic energy of that car is 5 × 10⁵ J

so

E₁ = $\frac{1}{2}$ mv²

we substitute

5 × 10⁵ = $\frac{1}{2}$ × m × ( 30.398 )²

5 × 10⁵ = m × 462.019

m = 5 × 10⁵ / 462.019

m = 1082.2065 kg

Now, Also given that; v₂ = 97 miles per hour = 43.362 meter per seconds

E₂ = $\frac{1}{2}$ mv₂²

we substitute

E₂ = $\frac{1}{2}$ × 1082.2065 × ( 43.362 )²

E₂ = $\frac{1}{2}$ × 1082.2065 × 1880.263

E₂ = 1.017 × 10⁵ J

Therefore, The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour

6 0

3 years ago

Suppose we are managing a consulting team of expert computer hackers, and each week we have to choose a job for them to undertak

lina2011 [118]

Answer:

if number == 1

then

tempSolution= max(l[number],h[number])

else if number == 2 then

tempSolution= max(optimalPlan(1, l, h)+ l[2], h[2])

else

tempSolution= max(optimalPlan(number − 1, l, h) + l[number], optimalPlan(number − 2, l, h) + h[number])

end if

return Value

FindOptimalValue(number, l, h)

for itterator = 1 ! number do

tempSolution[itterator] = 0

end for

for itterator = 1 ! number do

if itterator == 1 then

tempSolution[itterator] max(l[itterator], h[itterator])

else if itterator == 2 then

tempSolution[itterator] max(tempSolution[1] + l[2], h[2])

else

tempSolution[itterator] max(tempSolution[itterator − 1] + l[itterator], tempSolution[itterator − 2] + h[itterator])

end if

end for

return Value[number]

OPtimalPlan(number, l, h, Value)

for itterator = 1 ! number do

WeekVal[itterator]

end for

if tempSolution[number] − l[number] = tempSolution[number − 1] then

WeekVal[number] ”Low stress”

OPtimalPlan(number-1, l, h, Value)

else

WeekVal[number] ”High stress”

OPtimalPlan(number-2, l, h, Value)

end if

return WeekVal

7 0

3 years ago