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Mashcka [7]
3 years ago
5

WHICH OF THIS PLS FAST!!!

Engineering
1 answer:
Effectus [21]3 years ago
4 0

Answer:

A

Explanation:

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Explanation:

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2 years ago
A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is appli
Scrat [10]

Answer:

X_t=2.17391304*10^{-4}

X_r=2.89855072*10^{-4}

e_t=0.0026

e_r=0.0035

Explanation:

From the question we are told that:

Dimension 12*12

Thickness l_t=5mm=5*10^-3

Normal tensile force on top side F_t= 15kN

Normal tensile force on right side  F_r= 20kN

Elastic modulus, E=115Gpap=>115*10^9

Generally the equation for Normal Strain X is mathematically given by

 X=\frac{Force}{Area*E}

Therefore

For Top

 X_t=\frac{Force_t}{Area*E}

Where

 Area=L*B*T

 Area=12*10^{-2}*5*10^{-3}

 Area=6*10^{-4}  

 X_t=\frac{15*10^3}{6*10^{-4}*115*10^9}

 X_t=2.17391304*10^{-4}

For Right sideX_r=\frac{Force_r}{Area*E}

Where

Area=L*B*T

 Area=12*10^{-2}*5*10^{-3}

 Area=6*10^{-4}  

 X_r=2.89855072*10^{-4}

 X_r=2.89855072*10^{-4}

Generally the equation for elongation is mathematically given by

 e=strain *12

For top

 e_t=2.17391304*10^{-4}*12

 e_t=0.0026

For Right

 e_r=2.89855072*10^{-4} *12

 e_r=0.0035

5 0
3 years ago
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