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RideAnS [48]
3 years ago
11

A car is moving at 68 miles per hour. The kinetic energy of that car is 5 × 10 5 J.How much energy does the same car have when i

t moves at 97 miles per hour?
Engineering
1 answer:
Blababa [14]3 years ago
6 0

Answer:

The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour

Explanation:

Given the data in the question;

Initial velocity v₁ = 68 miles per hour = 30.398 meter per seconds

let mass of the car be m

kinetic energy of that car is 5 × 10⁵ J

so

E₁ = \frac{1}{2}mv²

we substitute

5 × 10⁵  = \frac{1}{2} × m × ( 30.398 )²

5 × 10⁵  = \frac{1}{2} × m × ( 30.398 )²

5 × 10⁵ = m × 462.019

m =  5 × 10⁵ / 462.019

m = 1082.2065 kg

Now, Also given that; v₂ = 97 miles per hour = 43.362 meter per seconds

E₂ = \frac{1}{2}mv₂²

we substitute

E₂ = \frac{1}{2} × 1082.2065 × ( 43.362 )²

E₂ = \frac{1}{2} × 1082.2065 × 1880.263

E₂ = 1.017 × 10⁵ J

Therefore, The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour

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Consider a single crystal oriented such that the slip direction and normal to the slip plane are at angles 42.7° and 48.3°, resp
icang [17]

Answer:

A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.

Explanation:

5 0
3 years ago
Please help me<br><br> there is no woodworking or woodshop choice
goldenfox [79]

Answer:

carpenter helped to set the cutr height and depth

what is its a jigsaw

Explanation:I took the test  

7 0
2 years ago
Dos capacitores de placas paralelas, idénticos, pero con la excepción de que uno tiene el doble de separación entre sus placas q
Charra [1.4K]

Las características de la capacitancia permiten encontrar los resultados para las diferentes preguntas

1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) El capacitor con menor distancia tiene mayor carga

3) El capacitor con menor distancia tiene mayor densidad de carga

Los capacitores son sistema que sirve para acumular carga, esa formado por placas conductoras separadas una distancia pequeña, la capacitancia es  

             C = \frac{Q}{DV} = \frac{\epsilon_o A}{d}  

Donde Q es a carga, ΔV la diferencia de potencial, A el area y d la separación de las placas.

Busquemos las respuestas para las diferentes preguntas:

1) Cual tiene mayor campo eléctrico.

El potencial y el campo eléctrico están relacionados

            ΔV = - E d

            E = - \frac{\Delta V}{d}

Indican que un capacitor tiene el doble de separación de las placas que el otro

Capacitor 1

          E = - \frac{\Delta V}{d_1}  

Capacitor 2

         d₂ = 2 d₁  

         E₂ = - \frac{\Delta V}{2d_1}  

         E₂= ½ E₁

Por lo tanto el capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) Cual tiene mas carga

Busquemos la carga para cada capacitor  

           Q = ε₀ \frac{A \Delta V}{d}  

Capacitor 1

           Q₁ = (ε₀ A ΔV) \frac{1}{d_1}

Capacitor 2

           Q₂ = (ε₀ A Δv) \frac{1}{2d_1}

           

            Q₂ = Q₁/2

       

El capacitor con menor distancia tiene mayor carga

3) Cual tiene mayor densidad de energía

La densidad de energía en un capacitor esta dada por

         u_E  = ½ ε₀ E²  

calculamos para cada capacitor

           

Capacitor 1

         u_{E\  1} = ½ ε₀ E₁²

Capacitor 2

         u_{E 2} = ½ ε₀ (E₁/2)²

por lo cual el capacitor con menor distancia tiene mas densidad de carga

En conclusión con lass característica de capacitancia podemos encontrar los resultados para las diferentes preguntas

     1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

    2) El capacitor con menor distancia tiene mayor carga

    3) El capacitor con menor distancia tiene mas densidad de carga  

Aprender mas aquí:  brainly.com/question/22813371

7 0
3 years ago
It has been estimated that 139.2x10^6 m^2 of rainforest is destroyed each day. assume that the initial area of tropical rainfore
Dmitry [639]

Answer:

A. 6.96 x 10^-6 /day

B. 22.466 x 10^12 m^2

C. 9.1125 x 10^14 kg of CO2

Explanation:

A. Rate of rainforest destruction = 139.2 x 10^6 m^2/day

Initial area of the rainforest = 20 x 10^12 m^2

Therefore to calculate exponential rate in 1/day,

Rate of rainforest destruction/ initial area of rainforest

= 139.2 x 10^6/20 x 10^12

= 6.96 x 10^-6 /day

B. Rainforest left in 2015 using the rate in A.

2015 - 1975 = 40 years

(40 * 365 )days + 10 days (leap years)

= 14610 days

Area of rainforest in 1975 = 24.5 x 10^12m^2

Rate of rainforest destruction = 139.2 x 10^6 m^2/day

Area of rainforest in 2015 = 14610 * 139.2 x 10^6

= 2.034 x 10^12 m^2

Area left = area of rainforest in 1975 - area of rainforest destroyed in 40years

= 24.5 x 10^12 - 2.034 x 10^12

= 22.466 x 10^12 m^2

C. How much CO2 will be removed in 2025

Recall: Photosynthesis is the process of plants taking in CO2 and water to give glucose and O2.

So CO2 removed is the same as rainforest removed so we use the rate of rainforest removed in a day

Area of rainforest in 1975 = 24.5 x 10^12 m^2

Area of rainforest removed in 2025 = 18262 days * 139.2 x 10^6

= 2.54 x 10^12 m^2

Area of rainforest removed between 1975 - 2025 = 24.5 x 10^12 - 2.54 x 10^12

= 21.958 x 10^12 mC2 of rainforest removed

CO2 = 0.83kg/m^2.year

CO2 removed between 1975 - 2025 = 0.83 * 21.958 x 10^12 * 50 years

= 9.1125 x 10^14 kg of CO2 was removed between 1975 - 2025

6 0
3 years ago
What is an engineer? <br>Answer within 2 hours please<br>(Simple question)
kvasek [131]

Answer:

Engineers, as practitioners of engineering, are professionals who invent, design, analyze, build and test machines, complex systems, structures, gadgets and materials to fulfill functional objectives and requirements while considering the limitations imposed by practicality, regulation, safety and cost

There are now six major branches of engineering: Mechanical, Chemical, Civil, Electrical, Management, and Geotechnical, and literally hundreds of different subcategories of engineering under each branch.

Explanation:

8 0
3 years ago
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