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larisa [96]
3 years ago
15

What types of mixtures are these? a cup of tea and sugar peanuts and almonds mixed together in a bowl a bucket full of sand and

gravel food coloring dissolved in water
Chemistry
1 answer:
Allushta [10]3 years ago
3 0

Answer:

The answer to your question is below

Explanation:

There are two kinds of mixtures

- Homogeneous is a mixture of two or more elements or compounds and its components can not be distinguished visually.

- Heterogeneous is a mixture of two or more elements or compounds and its components can be distinguished visually.

a cup of tea and sugar homogeneous

peanuts and almonds mixed together in a bowl heterogeneous

a bucket full of sand and gravel heterogeneous

food coloring dissolved in water homogeneous

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1-Bromopropane is treated with each of the following reagents. Draw the major substitution product if the reaction proceeds in g
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Answer:

Explanation:

If we look at the structure of 1-Bromopropane; we will see that it is a derivative of alkane family by the the substitution of an alkyl group. The position of the Bromine in the propane is 1, making 1-Bromopropane  a primary alkyl-halide.

Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used  otherwise it will result to a reactive mechanism if a weak electrophile is used.

However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.

The attached diagrams portraying this notions is shown in the attached file below.

5 0
3 years ago
An aqueous 0.300 M glucose solution is prepared with a total volume of 0.150 L. The molecular weight of
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Answer:

8.11g

Explanation:

Given parameters:

Molarity of aqueous solution = 0.3M

total volume  = 0.15L

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Mass of glucose needed in the solution = ?

Solution:

To solve this problem, we need to understand molarity.

Molarity is the number of moles of solute in a given volume of solution. In this problem, the solute here is the glucose and the solvent is water.

      Molarity  = \frac{number of moles of solute}{volume of solution}

A solution is made up of solute and solvent.

   now, let us solve for the number of moles of the solute which is glucose;

   Number of moles of glucose  = molarity x volume of solution;

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                                                      = 0.045mole

Now to find the mass of glucose;

        mass of glucose  = number of moles x molar mass

             input the parameters;

       

         Mass of glucose  = 0.045  x 180.16 = 8.11g

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