Question is incomplete, complete question is;
A 34.8 mL solution of 
(aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).
If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of 
? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.
Answer:
0.044 M is the molarity of (aq).
Explanation:
The reaction taking place here is in between acid and base which means that it is a neutralization reaction .
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
0.044 M is the molarity of (aq).
Answer: 833.3mmHg
Explanation:Please see attachment for explanation
Answer:
Bromine displaced iodide to form iodine
Explanation:
In this experiment, liquid bromine was allowed to react with a solution of potassium iodide.
Initially, we had a colorless 
solution which was mixed with light orange 
. If we add a light orange solution to a colorless solution, liquid bromine will get diluted and we'll see a slight decrease in its color intensity, however, if no reaction takes place, no color change will occur.
In the experiment, however, we examine a formation of a deep brown solution. Remember that iodine solution would form a brown solution.
As a result, bromine displaced iodide anion from potassium iodide:
the populations would rise and there would be no herbivore or omnivores
