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Mademuasel [1]
3 years ago
6

During an experiment, the percent yield of calcium chloride from a reaction was 82.38%. Theoretically, the expected amount shoul

d have been 105 grams. What was the actual yield from this reaction? CaCO3 + HCl → CaCl2 + CO2 + H2O
Chemistry
1 answer:
gregori [183]3 years ago
7 0

Answer:

Actual yield = 86.5g

Explanation:

Percent yield = 82.38%

Theoretical yield = 105g

Actual yield = x

Equation of reaction,

CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

Percentage yield = (actual yield / theoretical yield) * 100

82.38% = actual yield / theoretical yield

82.38 / 100 = x / 105

Cross multiply and make x the subject of formula

X = (105 * 82.38) / 100

X = 86.499g

X = 86.5g

Actual yield of CaCl₂ is 86.5g

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How many moles of a gas would occupy 22.4 Liters at 273 K and 1 atm?
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Answer:

1 mole of a gas would occupy 22.4 Liters at 273 K and 1 atm

Explanation:

An ideal gas is a set of atoms or molecules that move freely without interactions. The pressure exerted by the gas is due to the collisions of the molecules with the walls of the container. The ideal gas behavior is at low pressures, that is, at the limit of zero density. At high pressures the molecules interact and intermolecular forces cause the gas to deviate from ideality.

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In this case:

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Another way to get the same result is by taking the STP conditions into account.

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2 years ago
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Hi there,

the answer to the blank is: boiling point

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Hope this is correct :)

Have a great day

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