What sample size is needed so that the length of the interval is $60 with 95% confidence? We Assume: σ = $150.
Showing Work:
n ======> is the sample size we want to find:
N = ( z a/2^σ / E )^2
= ( 1.96 * 150 / 30 )^2 (margin of error is 1.96 times the standard error):
Answer: =======> 96.04 ≈ 97
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Step-by-step explanation:
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<span>Sixty percent of the days in the desert were hot and dry. Out of the 365 days, how many were hot and dry?
Solution is simple.
There are 365 days and 60% of those are hot and dry. What is 60% of 365?
365 x .60 = 219
</span>
The number of half page advertisements that Michael purchased is 4 while the full page advertisements is 11.
Let the number of half page ads be represented by h
Let the number of full page ads be represented by f.
Total number of advertisements = 15
h + f = 15 ....... (i)
h = 15 - f
Therefore, the system of equations to represent the situation will be:
60h + 100f = 1340 ........ (ii)
Put the value of h into equation (ii)
60(15 - f) + 100f = 1340
900 - 60f + 100f = 1340
Collect like terms
100f-60f = 1340-900
40f = 440
f = 11
The number of full-page advertisements that Michael purchased is 11.
Since h + f = 15
h + 11 = 15
h = 15 - 11
h = 4
The number of half page advertisements that Michael purchased is 5.
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