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alexgriva [62]
4 years ago
11

When the shadow of the moon appears on earths surface what is occuring?

Physics
1 answer:
Ket [755]4 years ago
6 0

The moon surface is visible to an observer on earth due to the gravitational force that attracts the moon to the earth. The more massive the body is, the more the smaller body is attracted to the larger body. We can only see the side of the moon due to the speed at which the moon rotates.

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What is the power of 4ohm resistor connected to a 12v battery?
NemiM [27]

Answer:

36watts

Explanation:

Data obtained from the question include:

R (Resistor) = 4 Ohms

V (Voltage) = 12V

P (power) =?

P = IV

Recall: I = V/R

P = V^2 /R

P = (12)^2 /4

P = 144/4

P = 36watts

Therefore, power is 36watts

8 0
3 years ago
Read 2 more answers
Physics help please! Offering 75 pts!
Nataliya [291]

Answer:

A

Explanation:

i got it from 2021 edge

5 0
3 years ago
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A train moving with a velocity of 42.9 km/hour North, increases its speed with a uniform acceleration of 0.250 m/s^2 North until
ankoles [38]

Answer:

3658.24m

Explanation:

Hello!

the first thing that we must be clear about is that the train moves with constant acceleration

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

\frac {Vf^{2}-Vo^2}{2.a} =X

Vf = final speed =160km/h=44.4m/s

Vo = Initial speed =42.9km/h=11.92m/s

A = acceleration =0.25m/s^2

X = displacement

solving

\frac {44.4^{2}-11.92^2}{2.(0.25)} =X\\X=3658.24m

the distance traveled by the train is 3658.24m

5 0
4 years ago
Find the expression for pressure exerted by fluid with proper description​
fredd [130]

Explanation:

The pressure exerted by a column of liquid of height h and density ρ is given by the hydrostatic pressure equation p = ρgh, where g is the gravitational acceleration

3 0
3 years ago
The Earth's Radius is 6.3710x106 m and mass is 5.9742x1024 kg. What is the acceleration due to gravity at Mount Everest (elevati
Shalnov [3]

Answer is

9.773m/s^2

-----------------------------------------------------------------------------

Given,

h=8848m

The value of sea level is 9.08m/s^2. So, Let g′ be the acceleration due to the gravity on Mount Everest.

g′=g(1 − 2h/h)

=9.8(1 - 6400000/17696)

=9.8(1 − 0.00276)

9.8×0.99724

=9.773m/s^2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s^2

-----------------------------------------------------------------------

hope this helps :)

3 0
3 years ago
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