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Eddi Din [679]
3 years ago
5

Dicuss the law of conservation of energy. Provide atleast one example that supports your description

Physics
2 answers:
yaroslaw [1]3 years ago
8 0
The Law of Conservation of Energy states that energy cannot be created or destroyed.

Ex: Electricity only changes forms (potential, kinetic, heat, etc...)
ozzi3 years ago
3 0
The law of conservation of energy<span> is a </span>law<span> of science that states that </span>energy<span> cannot be created or destroyed, but only changed from </span>one<span> form into another or transferred from </span>one<span> object to another.</span>
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A certain spring exerts a nonlinear force given by F(x) = −60x − 18x2 , where x is in meters and F is in newtons. A 0.90-kg bloc
tia_tia [17]

Answer:

a)  W = 6.75 J and b) v = 3.87 m / s

Explanation:

a) In the problem the force is nonlinear and they ask us for work, so we must use it's definition

      W = ∫ F. dx

Bold indicates vectors.  In a spring the force is applied in the direction of movement, whereby the scalar product is reduced to the ordinary product

     W = ∫ F dx

We replace and integrate

    W = ∫ (-60 x - 18 x²) dx

    W = -60 x²/2 -18 x³/3

Let's evaluate between the integration limits, lower W = 0 for x = -0.50 m, to the upper limit W = W for x = 0 m

    W = -30 [0- (-0.50) 2] -6 [0 - (- 0.50) 3]

    W = 7.5 - 0.75

    W = 6.75 J

b)  Work is equal to the variation of kinetic energy

    W = ΔK

    W = ΔK = ½ m v² -0

    v =√ 2W/m

    v = √(2 6.75/ 0.90)

    v = 3.87 m / s

8 0
3 years ago
A car with a constant velocity of 22 m/s is driven for 6.8 s. How far did it travel? (V =A d/AT)
SVEN [57.7K]

Answer: 150 m

Explanation:

velocity = 22 m/s

t = 6.8 s

velocity = \frac{distance}{time}

distance = velocity × time

= 22 × 6.8

= 149.6 m

≈ 150 m

option C

6 0
3 years ago
Consider two particles A and B. The angular position of particle A, with constant angular acceleration, depends on time accordin
Vera_Pavlovna [14]

Answer:

θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²

Explanation:

This is an angular kinematic exercise the equation for the angular position

the particle A

       θ = θ₀ + ω₀ t + ½ α t²

They say for the particle B

     w₀B = ½ w₀

     αB = 2 α

In addition, the particle begins at a time t_1 after particle A, in order to use the same timer, we must subtract this time from the initial

      t´ = t - t_1

l

et's write the equation of particle B

      θ = θ₀ + w₀B t´ + ½ αB t´2

replace

     θ = θ₀ + ½ w₀ (t -t_1) + ½ 2α (t -t_1)²

     θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²

4 0
3 years ago
Using the black numbers on the stopwatch to answer the questions. What is the most accurate reading of seconds as indicated by t
jenyasd209 [6]

a. 5.3

should be your answer

hope I Helped!!!!

4 0
3 years ago
How long would it take a person to come to a stop if they were going
hammer [34]
33 mins hope it’s right
8 0
3 years ago
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