Im just guessing, so i think is A
Answer:
16.8 g of AgCl are produced
Explanation:
The reactants are: NaCl and AgNO₃
The products are: AgCl, NaNO₃
Balanced equation: NaCl(aq) + AgNO₃(aq) → NaNO₃(aq) + AgCl(s) ↓
We convert the mass of AgNO₃ to moles → 10 g / 85g/mol = 0.117 moles
Ratio is 1:1, therefore 0.117 moles of nitrate will produce 0.117 moles of AgCl.
According to stoichiormetry.
We convert the moles to mass → 0.117 mol . 143.3g /1mol = 16.8 g
Answer:Speak English
Explanation: No speak Spanish
Answer:
3MnO₄⁻ + 24H⁺ + 5Au → 5Au³⁺ + 3Mn²⁺ + 12H₂O.
Explanation:
- KMnO₄ is strong oxidizing agent which is reduced and oxidizes Au according to the two-half reactions:
The oxidation reaction: Au → Au³⁺ + 3e.
The reduction reaction: MnO₄⁻ + 8H⁺ + 5e → Mn²⁺ + 4H₂O.
- To obtain the net redox reaction, we multiply the oxidation reaction by 5 and the reduction reaction by 5 to equalize the no. of electrons in the two-half reactions.
<em>So, the net redox reaction will be:</em>
<em>3MnO₄⁻ + 24H⁺ + 5Au → 5Au³⁺ + 3Mn²⁺ + 12H₂O.</em>
<em></em>
Answer:
Explanation:
The equation of the reaction:
Nitrogen gas N₂ reacts with Hydrogen as H₂ to produce ammonia NH₃;
N₂ + H₂ → NH₃
The balanced equation is ;
N₂ + 3H₂ → 2NH₃
The mole ratio is the ratio of the coefficients of the combining reactants;
1 mole of N₂ combines with 3 mole of H₂;
So;
