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lakkis [162]
3 years ago
8

1. Why is it that some combinations of ions do not seem to react while others result in precipitate? 2. For an insoluble compoun

d, how might you prevent formation of precipitate? 3. What conditions can you manipulate to make the precipitate more soluble? 4. Does the size of the crystal affect the solublization process? 5. How do you accurately rule out the presence of alkali metals in solution? 6. Which combinations of ions used do you expect to form insoluble salts? 7. What are their Ksp values?
Chemistry
2 answers:
trapecia [35]3 years ago
5 0
1. Some ions don't react and forms a precipitate because of the strengths of intermolecular bonds and the energy required to form new bonds.2. You can add another substance that will enable it to be dissolved in  the solution but this depends on the precipitate you have.3. There are many factors that will affect solubility this includes the temperature and the pressure which can be manipulated easily.4. Yes it affects the solubilization process. Surface area of the crystals is a factor.
N76 [4]3 years ago
3 0
1) Sometimes ions in solution react with each other to form a new substance that is insoluble (does not dissolve), called a precipitate.
2)<span>It depends on what kind of precipitate you're trying to prevent from forming. Many precipitates will dissolve in acidic solutions, so you could acidify the solution and see what happens. Other precipitates dissolve well when ammonia is added, so that's an option. There's no conclusive way to answer your question unless we know what kind of precipitate you're trying to prevent. 
</span>3) if a salt is deemed soluble macroscopically, very large number of ions dissolve before the solution reaches saturation
4)<span>if the temperature is decreased rapidly the solubility of your product will be significantly decreased in a short time (generally), thus the crystallization procedure will be accelerated leading smaller crystals. 

</span>
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3 years ago
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What is the balanced symbol equation for magnesium chloride + sodium carbonate --&gt; magnesium carbonate + sodium chloride
Semenov [28]

Answer:

MgCl₂+ Na₂CO₃ ==> MgCO₃ + NaCl

From a quick observation

You see that the right hand side of the eqn is deficient of Sodium and Chlorine

Simply Add a Coefficient of 2 to NaCl to balance it with the left.

Your answer now becomes

MgCl₂ + Na₂CO₃ ==> MgCO₃ + 2NaCl.✅

3 0
2 years ago
The pressure inside a pressure cooker is 2.0 atm. How many minutes will it take to cook 1.0 pound of potatoes in a pressure cook
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8 0
2 years ago
classify the following compounds as ionic (metal + nonmetal) , covalent (nonmetal + nonmetal) or both (compound containing a pol
musickatia [10]

Answer:

1. ionic

2. covalent

3. covalent

4. both

Explanation:

6 0
3 years ago
Balance this chemical equation.
Vadim26 [7]

Answer:

Explanation:

Reaction Given

    NaHCO₃ (s) + HC₂H₃O₂ (aq) -------> CO₂ (g) + H₂O (l) + NaC₂H₃O₂ (aq)

Balance Equation = ?

Solution:

Balance Chemical Equation:

A balanced chemical equation is that in which the number of the reactant atoms equal to the number of the product atom.

For example if the carbon at the reactant side is 3, the number of carbon must be 3 on the product side.

Check the chemical equation and count the number of atoms at the reactant side and product side.

If the number of atoms of the reactants equal to the number of atoms of products then the reaction is balanced but if not equal then reaction is not balanced

Balancing is an trial and error process to get a balance reaction.

First we count the number of atoms of reactant and product

Number of atoms of Reactant:

Na = 1

O = 5

H = 5

C = 3

Number of atoms of Product:

Na = 1

O = 5

H = 5

C = 3

So this a balance equation as the atoms of the reactant atom equal to the number of the product atoms.

Na atom is 1 on both reactant and product side

Oxygen atoms are 5 on reactant and 5 on product side

hydrogen atoms are 5 on reactant and 5 on product side

Carbon atoms are 3 on reactant and 3 on product side

So all the compounds in the reaction have 1 as its coefficient in the blanks

<u />

<u>1   </u>NaHCO₃ (s) +  <u>1  </u>HC₂H₃O₂ (aq) -----> <u>1  </u>CO₂ (g) + <u>1  </u>H₂O (l) + <u>1  Na</u>C₂H₃O₂ (aq)

7 0
3 years ago
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