Answer:
the first and last one on god
Step-by-step explanation:
Answer:
0.74 to 6.06
Step-by-step explanation:
The groups are independnet,
SE(xh bar-xa bar)=sqrt [sh^2/nh+sa^2/na]=sqrt [10.1^2/80+10.3^2/80]=1.61
At df=157, the t critical is 1.65
90%c.i=(xh bar-xa bar)+-tcritical SE(xh bar-xa bar)
=(25.2-21.8)+-1.65*1.61
=0.74 to 6.06
I believe that 6 3/7 is greater
Answer:
10.5 ft high
5.3 ft horizontally
Step-by-step explanation:
The equation can be written in vertex form to answer these questions.
f(x) = -0.2(x² -10.5x) +5
f(x) = -0.2(x² -10.5x +5.25²) +5 +0.2(5.25²)
f(x) = -0.2(x -5.25)² +10.5125
The vertex of the travel path is (5.25, 10.5125).
The maximum height is 10.5 feet, which occurs 5.3 feet (horizontally) from the point of release.
Answer: 10 inches
Step-by-step explanation:
We know that each single Denalia shell is 2 inches. So let's calculate how many inches a 25 shell necklace would be
25(number of shells)×2(inches per 1 shell) = 50in
Next let's find the second necklace with 20 shells
20(number of shells) × 2(inches per 1 shell) = 40in
Finally we take the difference between the two
50in - 40in = 10 inches
Thus, the difference between a 25 shell necklace and a 20 shell necklace is 10 inches.
