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Anuta_ua [19.1K]
3 years ago
9

10, 8, 6, ... Find the next term in the sequence.

Mathematics
2 answers:
valkas [14]3 years ago
6 0
Subtract 2 from each of the following numbers is the sequence so if you subtract 2 from six it will be 4 so the answer is 10, 8, 6 , 4
slega [8]3 years ago
5 0

Answer:

4, the answer is 4...

Step-by-step explanation:

The sequence is substracting 2 in each number...

10; 8; 6; 4...

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Divide<br><br> −4 1/3 ÷ −2 3/5
Alex777 [14]

Answer:

1 2/3

Step-by-step explanation:

-4 1/3 ÷ -2 3/5

-13/3 ÷ -13/5

-13 x 5/ 3x -13

-65/-39

1 2/3

5 0
3 years ago
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To describe a sequence of transformations that maps triangle ABC onto triangle A " B" C", a student starts with a reflection ove
irina1246 [14]

Answer:

no idea lol

Step-by-step explanation:

7 0
3 years ago
Find the values of m for which the lines y=mx-2 are tangents to the curve with equation y=x^2-4x+2
deff fn [24]

Let y= mx-2 be the tangent line to y=x^2-4x+2 at x=a.

Then slope, m=\frac{dy}{dx} at x=a = 2a-4.

Hence the equation is y=(2a-4)x-2

Let's find y-coordinate at x=a using tangent line and curve.

Using tangent line y at x=a is (2a-4) a -2 =2a^{2}-4a-2

Using given curve y-coordinate at x=a is a^{2}-4a+2

Let's equate these 2 y-coordinates,

 2a^{2} -4a-2 = a^{2} -4a+2

2a^{2}-a^{2} = 2+2

a^{2}=4

a=2 or -2.

If a=2, m=2a-4 = 2*2-4=0

If a=-2,m= 2(-2)-4 = -8

Hence m values are 0 and -8.

8 0
4 years ago
Can someone help I think I know the answer but I have one more time to get it wrong
zvonat [6]

Answer:

23+(6x+1)=90 is the equation

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which expression defines Sn for an = 5(1/3)^n?
disa [49]

If the first term is 5/3 and the common difference is 1/3. Then the infinite sum of the geometric series will be 2.5.

<h3>What is a series?</h3>

The sum of sequence terms is a series. That is, it is a list of integers connected by addition operations.

The sequence is given in the form of a variable.

\rm a_n = 5 \left (\dfrac{1}{3} \right)^{n}

The first term will be

\rm a_1 =\dfrac{5}{3}

And the common ratio will be

\rm r =\dfrac{1}{3}

Then the sum of the geometric series will be given as

\rm S_{\infty} = \dfrac{a_1}{1-r}\\\\\\S_{\infty} = \dfrac{5/3}{1-1/3}\\\\\\S_{\infty} = \dfrac{5/3}{2/3}\\\\\\S_{\infty} = \dfrac{5}{2}\\\\\\S_{\infty} = 2.5

More about the series link is given below.

brainly.com/question/10813422

#SPJ1

4 0
2 years ago
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