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3 years ago

7

What is 6/7 Answer quickly please!!

1 answer:

nevsk [136]3 years ago

6 0

Answer: 0.8

Step-by-step explanation:

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PLEASE HELP ASAP 50 POINTS BRAINLIEST IF CORRECT

beks73 [17]

I think the answer is B

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3 years ago

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PLEASE HELPPP ASAP, NEED THIS DUEEE ASAP

valentina_108 [34]

Answer:

Proportional relationship.

Step-by-step explanation:

From the given table, let us find the ratio of each pair of time and distance.

The first pair is 2 and 90.

Therefore, the ratio is $r=\frac{90}{2}=45$

The second pair is 3 and 135.

Therefore, the ratio is $r=\frac{135}{3}=45$

The third pair is 5 and 225.

Therefore, the ratio is $r=\frac{225}{5}=45$

The fourth pair is 6 and 270.

Therefore, the ratio is $r=\frac{270}{6}=45$

Since, the ratio of each pair is same and equal to 45, therefore, the relationship is proportional relationship.

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3 years ago

Please help me with this homework

andriy [413]

Answer:

wow. at this point just guess

Step-by-step explanation:

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3. Cal spent 2/3 of an hour working on his car. How many minutes did Cal spend working

jolli1 [7]

40 minutes because 1/3 is 20 minutes because an hour is 60 minutes

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3 years ago

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Which equation represents a graph with a vertex at (–3, 2)?

lesya [120]

<u>We will proceed to find the equations in the vertex form in each case</u>

<u>Part a)</u> $y= 4x^{2}+24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}+24x$

Factor the leading coefficient

$y-38= 4(x^{2}+6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}+6x+9)$

$y-2= 4(x+3)^{2}$

$y= 4(x+3)^{2}+2$

<u>the vertex is the point $(-3,2)$ </u>

<u>Part b)</u> $y=4x^{2}-24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}-24x$

Factor the leading coefficient

$y-38= 4(x^{2}-6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}-6x+9)$

$y-2= 4(x-3)^{2}$

$y= 4(x-3)^{2}+2$

<u>the vertex is the point $(3,2)$ </u>

<u>Part c) </u> $y=4x^{2}+12x+2$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-2= 4x^{2}+12x$

Factor the leading coefficient

$y-2= 4(x^{2}+3x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-2+9= 4(x^{2}+3x+2.25)$

$y+7= 4(x+1.5)^{2}$

$y= 4(x+1.5)^{2}-7$

<u>the vertex is the point $(-1.5,7)$ </u>

<u>Part d)</u> $y=4x^{2}+16x+13$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-13= 4x^{2}+16x$

Factor the leading coefficient

$y-13= 4(x^{2}+4x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-13+16= 4(x^{2}+4x+4)$

$y+3= 4(x+2)^{2}$

$y= 4(x+2)^{2}-3$

<u>the vertex is the point $(-2,-3)$ </u>

therefore

<u>the answer is </u>

$y= 4x^{2}+24x+38$

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3 years ago

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