In order to determine the number of boys in the class, first, we set-up an algebraic equation. Let x = number of boys in the class. The equation is then: x + 4x = 45. This is because the number of girls is 4 times greater than the number of boys. After solving the algebraic equation, it is then determined that there are 9 boys in the Chemistry class.
Principal is the same as original amount.
<span>1. You convert the rate % to a decimal number. (divide by 100) </span>
<span>2. Substitute: </span>
<span>P = 144 / (.04 x 2) </span>
<span>3. Solve: </span>
<span>P = 144 / .08 </span>
<span>P = 1,800 </span>
<span>4. Your answer is $1,800</span>
Answer:
Sue would have taken 15 hours to sew all the costumes.
Step-by-step explanation:
In 10 hours, Sue sewed 5 costumes (1 every 2 hours).
Sue= 5 costumes
Sue sewed in 10 hours, twice as many costumes as Anne in 16 hours. Then 5 is twice costumes than Anne produced. Therefore, Anne sewed 2.5 costumes.
Anne: 2.5 costumes
In total they had to sew 5+2.5= 7.5 costumes. Then Sue would have taken 7.5*2= 15 hours to sew them all.
1. 40
2. 24
3. 7.5
4. 30
5. 22.5
Answer:
The first one
Step-by-step explanation:
2y + 4x = -5
2y = -5 - 4x
y = - (5/2) - 2x
