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Fed [463]
3 years ago
13

first three terms of a sequence are given. Round to the nearest thousand (if necessary) 152,149,146... Find the 30th term

Mathematics
1 answer:
Cloud [144]3 years ago
4 0

Answer:

65

Step-by-step explanation:

use the following equation

aₙ=a₁+(n-1)d

Where d is the common difference

n is the term

a₁ is the first term

the common difference is -3 (149-152)

this means we have

152+(30-1)*-3

Compute this and get

65

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8 0
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The tax rate is 3.9%<br> What is the tax on 42$? <br> Round to the nearest hundredth
mafiozo [28]
To find the total price, we use this equation:
42 + 0.039(42)
We can make it simpler:
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7 0
4 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
Find the volume of the triangular prism
jonny [76]

Answer:

Step-by-step explanation:

Ok so first we need to look and rule out the ones that are not correct like 9m and 5m. ok now we ruled out 2 of the wrong ones and now we have 90m and it looks like a 45m. now we multiply 5 x 2 x 9 which equals 90. so the answer is 90.

                        Hope it helps!

6 0
3 years ago
Read 2 more answers
2/3 (5 x 4) ÷ 3 + 6/7 =
Lerok [7]
334/63
if u want the mixed fraction it'd be 5(19/63)
6 0
4 years ago
Read 2 more answers
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