264 grams of Carbon dioxide (CO2) are needed to create a 40M solution in 150ml of solution.
Explanation:
Given :
molarity of the solution = 40M
Volume of the solution = 150ml or 0.15 litres after dividing it by 1000
compound is carbon dioxide
atomic mass of CO2 = 44.01 gram/mole
mass of CO2 = ?
moles of Co2 =?
the relation between grams and molarity is given by:
number of moles = equation 1
molarity is given by :
Molarity = equation 2
Putting the value of number of moles in equation 2
molarity =
mass = molarity x atomic mass x volume
mass = 40 x 0.15 x 44.01
= 264 grams
264 grams is the mass of carbon dioxide required to make a solution of 40 M in 150 ml of solution.
The initial density of the fluid is 100 grams per 8 ounce.
100 grams/ 8 ounce * (1 ounce/29.5735 ml) = 0.4227 g/ml
if transferred to a 16-ounce glass:
100 grams/16 ounces * (1 ounce/29.5735ml) = 0.2113 g/ml
therefore, the change is 0.4227g/ml - 0.2113 g/ml = 0.2113 g/ml
Answer:
protons neutrons and electrons
Answer:
Volumen C6H8O6(sln) = 2.569 L ≅ 2.6 L
Explanation:
vitamin C ≡ ascorbic acid (C6H8O6)
∴ vitamin C/daily = 75.0 mg/d
∴ molar mass C6H8O6 = 176.12 g/mol
solution:
∴ <em>C</em> C6H8O6 = 0.002486 mol/L
⇒ ppm C6H8O6 = (0.002486 mol/L)*(176.12 g/mol)*(1000 mg/g)
⇒ ppm C6H8O6 = 437.834 mg/L
for a 15.0 day:
⇒ Volume C6H8O6(sln) = (75.0 mg/d)*(L/437.834 mg)*(15.0 d)
⇒ Volume C6H8O6(sln) = 2.569 L