Which of the following is NOT a developer of an atomic model?

Four students are carrying out different laboratory procedures.

leva [86]

B. Jason's experiment

3 0

4 years ago

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How much work is done in accelerating a 2000 kg car from rest to a speed of 30 m/s?

Otrada [13]

The work done is the same as the amount of energy increase. The formula for kinetic energy is 122
1
2
m
v
2
.

The initial KE of the car is 12(1000)×202=200,000
1
2
(
1000
)
×
20
2
=
200
,
000
joules.

The final KE of the car is 12(1000)×302=450,000
1
2
(
1000
)
×
30
2
=
450
,
000
joules.

The difference between these is the amount of work done: 450,000−200,000=250,000
450
,
000
−
200
,
000
=
250
,
000
joules.
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8 0

3 years ago

Describe one example of light being refracted in the living room

Sloan [31]

Answer:

television

Explanation:

a television refracts light (the light bounces off of the screen

3 0

3 years ago

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We divide the electromagnetic spectrum into six major categories of light, listed below. Rank these forms of light from left to

IRINA_888 [86]

Answer:

(1.) gamma rays. (2.) X-rays. (3.) ultraviolet. (4.) visible light. (5.) infrared.

(6.) radio waves

Explanation:

Notice that these wavelengths span an enormous range. The wavelengths of gamma rays can be smaller than the size of an atomic nucleus, while the wavelengths of radio waves can be many meters (or even milometers) long. Visible light spans only a very narrow range of wavelengths, from about 400 nano meters at the blue (violet) end to about 700 nano meters at the red end.

4 0

3 years ago

How many electrons or protons are found in

raketka [301]

a) $6.25\cdot 10^{18}$ protons

b) $6.25\cdot 10^{18}$ electrons

c) 1 electron

Explanation:

a)

In this problem, the electric charge that we have is:

$Q=+1 C$

First of all, we observe that this charge is positive: this means that it will consist of protons.

In fact, protons are positively charged particles that reside in the nuclei of the atoms. The charge of one proton is

$q_p = +1.6\cdot 10^{-19}C$

which is also known as fundamental charge.

Therefore, we can write the charge Q as consisting of the charge of several protons:

$Q=N q_p$

where N is the number of protons.

And solving for N,

$N=\frac{Q}{q_p}=\frac{+1}{+1.6\cdot 10^{-19}}=6.25\cdot 10^{18}$

b)

Here the total charge is

$Q=-1C$

The total charge here is negative: this means that it consists of electrons. Electrons are negatively charged particles that orbit around the nucleus in an atom; the charge of one electron is

$q_e = -1.6\cdot 10^{-19}C$

So, its charge is opposite to that of the proton.

Therefore, we can write the charge Q as the sum of the charges of N electrons:

$Q=Nq_e$

Where N is the number of electrons.

And solving for N, we find:

$N=\frac{Q}{q_e}=\frac{-1}{-1.6\cdot 10^{-19}}=6.25\cdot 10^{18}$

c)

In this case, the total net charge is

$Q=-1.6\cdot 10^{-19} C$

As in part b), we notice that the total charge is negative. Therefore, it will consist of N electrons (negatively charged particles), such that we have

$Q=Nq_e$

where

$q_e = -1.6\cdot 10^{-19}C$ is the charge of one electron

N is the number of electrons

And solving for N, we find:

$N=\frac{Q}{q_e}=\frac{-1.6\cdot 10^{-19}}{-1.6\cdot 10^{-19}}=1$

So, 1 electron.

3 0

3 years ago