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NISA [10]
3 years ago
7

Which of the following is NOT a developer of an atomic model?

Physics
1 answer:
MatroZZZ [7]3 years ago
6 0
B) Planck. He is not a developer of an atomic model.
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ANSWER ASAP 50 POINTS
spin [16.1K]

Answer:It turns out the Venus flytrap is a power plant, capable of generating electrical signals. Each trap is actually a modified leaf: a hinged midrib, which would be the central vein of a more familiar leaf, joins the two lobes, which secrete a sweet sap to attract insects.

Explanation:The leaves of Venus' Flytrap open wide and on them are short, stiff hairs called trigger or sensitive hairs. When anything touches these hairs enough to bend them, the two lobes of the leaves snap shut trapping whatever is inside.

4 0
3 years ago
If a proton were released from rest at the sphere's surface, what would be its speed far from the sphere?
balu736 [363]

Let the sphere is having charge Q and radius R

Now if the proton is released from rest

By energy conservation we can say

U = K

\frac{kQe}{R} = \frac{1}{2}mv^2

\frac{2kQe}{mR} = v^2

now take square root of both sides

v =\sqrt{\frac{2kQe}{mR}}

so the proton will move by above speed and

here Q = charge on the sphere

R = radius of sphere

k = 9 * 10^9


5 0
3 years ago
Read 2 more answers
Four students are each pushing on one side of a box. Mara is pushing to the west, Cindi is pushing to the east, Chris is pushing
jenyasd209 [6]

Answer:

cindi

Explanation:

cindi's work done is larger than all the other students combined

5 0
3 years ago
Vector A has a magnitude of 30 units. Vector B is perpendicular to vector Aand has a magnitude of 40 units. What would the magni
Fudgin [204]

Answer:

|\vec A + \vec B| = 50 units

Explanation:

As we know that magnitude of two vectors is given as

|\vec A + \vec B| = \sqrt{A^2 + B^2 + 2AB cos\theta}

here we know that

A = magnitude of vector A

B = magnitude of vector B

\theta = angle between two vectors

so here we know that

A = 30 units

B = 40 units

angle = 90 degree

so we have

|\vec A + \vec B| = \sqrt{30^2 + 40^2 + 2(30)(40)cos90}

|\vec A + \vec B| = \sqrt{30^2 + 40^2}

|\vec A + \vec B| = 50 units

3 0
3 years ago
Your friend says that if Newton’s third law is correct, no object would ever start moving. Here is his argument: You pull a sled
m_a_m_a [10]

Answer:

Explanation:

You pull a sled exerting a 50 N force on it , sled also exerts a force on you . These forces are action and reaction force , as per third law of Newton . These two forces are equal and  opposite . But they do not act on the same object so they do not cancel each other . They act on different objects , one on the sledge and the other on you . Due to force on sledge , sledge moves in the direction of force or towards you . You will start moving in opposite direction if frictional force of ground is nil or less .

6 0
3 years ago
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