The part that moves are called anti-nodes. The stationary pars are nodes
F = 1440 N. The repulsion force between two identical charges, each -8.00x10⁻⁵C separated by a distance of 20.0 cm is 1440 N.
The easiest way to solve this problem is using Coulomb's Law given by the equation 
, where k is the constant of proportionality or Coulomb's constant, q₁ and q₂ are the charges magnitude, and r is the distance between them.
We have to identical charges of -8.00x10⁻⁵C, are separated by a distance of 20.0 cm, and we need to know the force of repulsion between the charges.
First, we have to convert 20.0 cm to meters.
(20.0 cm x 1m)/100cm = 0.20 m
Using the Coulomb's Law equation:
Longshore currents are affected by the velocity and angle of a wave. When a wave breaks at a more acute (steep) angle on a beach, encounters a steeper beach slope, or is very high, longshore currents increase in velocity. ... This process, known as “longshore drift,” can cause significant beach erosion.
Answer:
(D) Car A is not accelerating, but car B is accelerating.
Explanation:
One pitcher contains 12 glasses of lemonade . And she serves 4 glasses of lemonade .
It is given that remaining number of glasses of lemonade = g
And we need to write an solve an equation , which gives the value of g.
And g equals to the difference of total lemonade and served lemonade, that is
So she can serve 8 more glasses of lemonade .
