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Mandarinka [93]
4 years ago
10

The outer surface of the cardboard center of a paper towel roll: a. cannot be a Gaussian surface since it is an insulator. b. is

a possible Gaussian surface. c. cannot be a Gaussian surface because it is not a closed surface. d. none of the other responses. e. cannot be a Gaussian surface because it encloses no charge.
Physics
1 answer:
zvonat [6]4 years ago
5 0

Option C

The outer surface of the cardboard center of a paper towel roll: cannot be a Gaussian surface because it is not a closed surface.

<h3><u>Explanation:</u></h3>

A Gaussian surface is a bounded surface, ie. an impounded plain, bounded by space which can be practiced in obtaining out the mass of flux of electric, gravitational, or any additional field.

It should be closed surface so that a precise estimation can be performed within points that are inside the cover, on the surface, and outside the cover is the prime part of this. In this problem with considering that paper towel roll is not a closed surface, it is not a gaussian surface.

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Superconducting materials can transport electrons with no resistance, and hence release no heat, sound, or other energy forms. Superconductivity occurs at a specific material's critical temperature (Tc). As temperature decreases, a superconducting material's resistance gradually decreases until it reaches critical temperature. At this point resistance drops off, often to zero, as shown in the graph at right.

Explanation:

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3 years ago
What a neurology professor does = _______ brains
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3 years ago
Water can dissolve almost anything in the universe
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Answer:

No, its not possible for water to dissolve almost anything in the universe.

Explanation:

Solubility of a solute defines the ability of that solute to dissolve in a given solvent. It is defined as the maximum amount of solute dissolved in a solvent at equilibrium. The solution which results from dissolving this maximum amount is called a saturated solution, and one it has been reached, no more solute can be dissolved in it.

Different substances in the universe have diffferent solubilities in water, some very high (soluble) (eg. sugar and salt) and some very low (insoluble) (eg plastics). The substances that are able to form bonds with water (Hydrogen or Ionic) are more soluble than those who are not able to do so.

5 0
3 years ago
a 2100-kg car drives with a speed of 18 m/s onb a flat road around a curve that has a radius of curvature of 83m. The coefficien
Law Incorporation [45]

Answer:

<u>The magnitude of the friction force is 8197.60 N</u>

Explanation:

Using the definition of the centripetal force we have:

\Sigma F=ma_{c}=m\frac{v^{2}}{R}

Where:

  • m is the mass of the car
  • v is the speed
  • R is the radius of the curvature

Now, the force acting in the motion is just the friction force, so we have:

F_{f}=m\frac{v^{2}}{R}

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F_{f}=8197.60 \: N

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I hope it helps you!

7 0
3 years ago
A ball is launched with initial speed v from ground level up a frictionless slope (This means the ball slides up the slope witho
amid [387]

Answer:

hmax = 1/2 · v²/g

Explanation:

Hi there!

Due to the conservation of energy and since there is no dissipative force (like friction) all the kinetic energy (KE) of the ball has to be converted into gravitational potential energy (PE) when the ball comes to stop.

KE = PE

Where KE is the initial kinetic energy and PE is the final potential energy.

The kinetic energy of the ball is calculated as follows:

KE = 1/2 · m · v²

Where:

m = mass of the ball

v = velocity.

The potential energy is calculated as follows:

PE = m · g · h

Where:

m = mass of the ball.

g = acceleration due to gravity (known value: 9.81 m/s²).

h = height.

At  the maximum height, the potential energy is equal to the initial kinetic energy because the energy is conserved, i.e, all the kinetic energy was converted into potential energy (there was no energy dissipation as heat because there was no friction). Then:

PE = KE

m · g · hmax = 1/2 · m · v²

Solving  for hmax:

hmax = 1/2 · v² / g

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4 years ago
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