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Alexus [3.1K]
3 years ago
8

A clock which has brass pendulum beats correctly at 30C will it run faster or slower if temperature increase or decrease​

Physics
1 answer:
Dominik [7]3 years ago
7 0

Answer:

We know that the period of a pendulum is written as:

T = 2*pi*√(L/g)

where:

g = gravitational acceleration = 9.8m/s^2

pi = 3.1415...

L =  length of the pendulum, in this case, is the length of the brass pendulum.

Now, we know that the brass dilates when the temperature increases.

Then if the temperature increases, the value of L will increase, which means that the period T will also increase, because L is in the numerator of T.

If the period increases the complete motion of the pendulum needs more time, this would mean that the clock will run slower.

If the temperature decreases, the opposite occurs, the value of L decreases, and then the period also decreases, which means that the clock will run faster.

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To solve this problem we will apply the concept of magnification, which is given as the relationship between the focal length of the eyepieces and the focal length of the objective. This relationship can be expressed mathematically as,

\mu = \frac{f_0}{f_e}

Here,

\mu = Magnification

f_e = Focal length eyepieces

f_0 = Focal length of the Objective

Rearranging to find the focal length of the objective

f_0 = \mu f_e

Replacing with our values

f_0 = 7.5* 3.7cm

f_0 = 27.75cm

Therefore the focal length of th eobjective lenses is 27.75cm

5 0
3 years ago
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enot [183]

Answer:

As Per Provided Information

Moving body has 2m/s² acceleration

Time taken by body is 4 second

We are asked to find the 'change in velocity' ( ∆V) by the body.

<u>Formula Used here</u>

\boxed{\bf{\Delta \: V \:  =  acceleration \:  \times time \:}}

<u>Substituting </u><u>the </u><u>given </u><u>value</u>

<u>\sf\longrightarrow\Delta\:V \:  = 2 \times 4 \\  \\  \\ \sf\longrightarrow\Delta\:V \:  =8m {s}^{ - 1}</u>

<u>Therefore</u><u>,</u>

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Option a is right answer that is reverse osmosis.
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Hope this helps!
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