Answer:
P₂ = 1.22 kPa
Explanation:
This problem can be solved using the equation of state:

where,
P₁ = initial pressure = 1 KPa
P₂ = final pressure = ?
V₁ = initial Volume = 1 liter
V₂ = final volume = 1.1 liter
T₁ = initial temperature = 290 k
T₂ = final temperature = 390 k
Therefore,

<u>P₂ = 1.22 kPa</u>
Answer:
I think the answer is C.
Explanation:
A primary source is a first hand account of an event while a secondary source is a retelling or second hand account meaning as many details will be prevalent.
To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.
Gravitational potential energy can be defined as

As M=m, then

Where,
m = Mass
G =Gravitational Universal Constant
R = Distance /Radius
PART A) As half its initial value is u'=2u, then



Therefore replacing we have that,

Re-arrange to find v,



Therefore the velocity when the separation has decreased to one-half its initial value is 816m/s
PART B) With a final separation distance of 2r, we have that

Therefore




Therefore the velocity when they are about to collide is 