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klio [65]
3 years ago
8

What is an electric motor? Explain its operation. 2-3 sentence

Physics
2 answers:
ASHA 777 [7]3 years ago
8 0

An electric motor is electric machinery that converts electrical energy supplied to it to mechanical energy.

It works on the principle of applying a magnetic field in electromagnetism.

A current-carrying loop is exposed to a magnetic field which results in torque.

The torque formed rotates the coil which is then followed by rotation of propellers as the current passes through the loop.

Explanation

An electric motor consist of a rotor- a moving part, commutator, brushes, axle, field-magnet, power supply and a stator- a part going around the rotor.

Anarel [89]3 years ago
4 0

Answer:

An electric motor is a device that changes electrical energy into mechanical energy. This change occurs due to the interaction between the magnetic field of magnets and the magnetic field due to the  electric current in the  loop. The interaction between the two produces a torque that makes the loop rotate on a shaft.

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A 10-kg package drops from chute into a 25-kg cart with a velocity of 3 m/s. The cart is initially at rest and can roll freely w
amid [387]

Answer:

(a) the final velocity of the cart is 0.857 m/s

(b) the impulse experienced by the package is 21.43 kg.m/s

(c) the fraction of the initial energy lost is 0.71

Explanation:

Given;

mass of the package, m₁ = 10 kg

mass of the cart, m₂ = 25 kg

initial velocity of the package, u₁ = 3 m/s

initial velocity of the cart, u₂ = 0

let the final velocity of the cart = v

(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;

m₁u₁  + m₂u₂ = v(m₁  +  m₂)

10 x 3   + 25 x 0   = v(10  +  25)

30  = 35v

v = 30 / 35

v = 0.857 m/s

(b) the impulse experienced by the package;

The impulse = change in momentum of the package

J = ΔP = m₁v - m₁u₁

J = m₁(v - u₁)

J = 10(0.857 - 3)

J = -21.43 kg.m/s

the magnitude of the impulse experienced by the package = 21.43 kg.m/s

(c)

the initial kinetic energy of the package is calculated as;

K.E_i = \frac{1}{2} mu_1^2\\\\K.E_i = \frac{1}{2} \times 10 \times (3)^2\\\\K.E_i = 45 \ J\\\\

the final kinetic energy of the package;

K.E_f = \frac{1}{2} (m_1 + m_2)v^2\\\\K.E_f = \frac{1}{2} \times (10 + 25) \times 0.857^2\\\\K.E_f = 12.85 \ J

the fraction of the initial energy lost;

= \frac{\Delta K.E}{K.E_i} = \frac{45 -12.85}{45} = 0.71

7 0
3 years ago
A capoeira é muito mais que uma luta, por isso os campeonatos internos tem o objetivo de: 1 ponto Testar a força dos participant
timurjin [86]

Answer:

Avaliar o indivíduo como um todo.

Explanation:

O graduado na capoeira, é uma pessoa que recebe mais respeito pelo grupo. Sendo portanto o objetivo de cada exame interno, ou pelo menos deveria ser em sua vasta maioria avaliar o indivíduo como um todo.

8 0
3 years ago
The brick wall (of thermal conductivity 0.35 W/m ·◦ C) of a building has dimensions of 2.7 m by 6 m and is 16 cm thick. How much
Gwar [14]

Answer:

Q = 54.577\,MJ

Explanation:

The heat transfer through brick wall is:

\dot Q = \frac{k\cdot A}{L}\cdot \Delta T

\dot Q = \frac{\left(0.35\,\frac{W}{m\cdot ^{\circ}C} \right)\cdot (2.7\,m)\cdot (6\,m)}{0.16\,m} \cdot (31^{\circ}C - 8^{\circ}C)

\dot Q = 815.063\,W

The heat flow in a 18.6-h period is:

Q = \dot Q \cdot \Delta t

Q = (815.063\,W)\cdot (18.6\,h)\cdot \left(\frac{3600\,s}{1\,h} \right)

Q = 54576618.48\,J

Q = 54.577\,MJ

8 0
3 years ago
Read 2 more answers
Người ta ném một hòn bi theo phương ngang với vận tốc ban đầu là 15m/s và nó rơi xướng đất sau 4s. Bỏqua sức cản của không khí v
Juliette [100K]

Answer:

h = 80m L = 60m

Explanation:

Độ cao Ng ta ném hòn bi là

t=\sqrt{\frac{2h}{9}} => 4^2 = \frac{2h}{10}

h= 80m

Tầm bay xa:

L= Vo . t = 15.4 = 60m

Chúc học tốt nghen

5 0
3 years ago
Light from a laser strikes a diffraction grating that has 5500 lines per centimeter. The central and first-order maxima are sepa
WINSTONCH [101]

.Answer:

491.4 nm

Explanation:

The distance between central and first maxima is,

y=0.455m

And the distance between screen abnd grating is,

L=1.62 m

Now the angle can be find as,

tan\theta=\frac{y}{L} \\\theta=tan^{-1}(\frac{0.455}{1.62})  \\\theta=15.68^{\circ}

Now the grating distance is,

d=\frac{1}{5500} cm\\d=1.82\times 10^{-6}m

Now with m=1 condition will become,

\lambda=dsin\theta

So,

\lambda=1.82\times 10^{-6}m\times sin(15.68^{\circ})\\\lambda=1.82\times 10^{-6}m\times 0.270\\\lambda=491.4\times 10^{-9}m\\\lambda=491.4 nm

Therefore the wavelength of laser light is 491.4 nm.

3 0
3 years ago
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