Answer:
T = 3.75 K
Explanation:
As we know
PV = nRT
R =8.3144598 J. mol-1. K-1
P = 0.562 atm
V = 83.3 mL
moles in 0.392 g of I2 = 0.392/mass of I2 = 0.392 grams/253.8089 g/mol = 0.0015 moles
Substituting the given values, we get
0.562 atm * 83.3 *10^-3 L = 0.0015 moles * 8.3144598 J. mol-1. K-1 * T
T = 3.75 K
The maximum temperature : a. 745 K
<h3>Further explanation</h3>
Given
Gas at 25°C(298 K) and at a pressure of 0.800 atm
Final pressure = 2 atm
Required
Final temperature
Solution
Gay Lussac's Law
When the volume is not changed, the gas pressure in the vessel is proportional to its absolute temperature
Input the value :
T₂=(P₂T₁)/P₁
T₂=(2 atm x 298 K)/0.8 atm
T₂ = 745 K = 472 °C
Charle's law states the relationship between the temperature and the volume of the gas. The final volume occupied at 120 °C is 0.20 L.
<h3>What is Charle's law?</h3>
Charle's law is the ideal gas law that states the relationship between the volume of the gas occupied at a temperature.
Given,
V1 = 0.75 L
T1 = 1443 .15 K
T2 = 393.15 K
The final volume is calculated as:
(V1 × T2) ÷ T1
= 0.75 × 393.15 ÷ 1443.15
= 0.20 L
Therefore, 0.20 L is the final volume.
Learn more about Charle's law here:
brainly.com/question/14517633
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Answer:
1 year- 1 mole
time in general- amount of matter
1 second- 1 atom/ particle
