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guajiro [1.7K]
3 years ago
14

The amount of heat involved in the synthesis of 1 mole of a compound from its elements, with all substances in their standard st

ates at 25°C, is called _____.
A) standard heat of formation


B) heat of solidification


C) enthalpy


D) heat of reaction
Chemistry
2 answers:
Pachacha [2.7K]3 years ago
8 0

Answer:

A

Explanation:

goblinko [34]3 years ago
6 0

Answer:

A) standard heat of formation

Explanation:

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In 0.190 mole of C6H14O, there is 0.190*6 (number of C in one molecule) = 1.140 mole of C atoms. The total number of C atoms = 1.14 * 6*10^{23} (atoms of C in one mole) = 6.84*10^{23} atoms. 
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Which of the following BEST supports the Big bang theory of the origin of the universe?
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Explanation:

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I don't really understand this worksheet question.​
Citrus2011 [14]
25/2 and 96/X
CROSS MULTIPLY.

2x=2,400.
divide by 2.
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What features make a question scientific, and why are some questions beyond the boundaries of scientific investigation?
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The scientific method                                  


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3 years ago
The two naturally occuring isotopes of antimony are 121Sb (57.21%) and 123Sb (42.79%), with isotopic masses of 120.904 and 122.9
emmasim [6.3K]

Answer:

The average atomic weight = 121.7598 amu

Explanation:

The average atomic weight of natural occurring antimony can be calculated as follows :

To calculate the average atomic mass the percentage abundance must be converted to decimal.

121 Sb has a percentage abundance of 57.21%, the decimal format will be

57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .

123 Sb has a percentage abundance of 42.79%, the decimal format will be

42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .

Next step is multiplying the fractional abundance to it masses

121 Sb = 0.5721 × 120.904 = 69.169178400

123 Sb = 0.4279 × 122.904 = 52.590621600

The final step is adding the value to get the average atomic weight.

69.169178400 + 52.590621600 = 121.7598 amu

5 0
3 years ago
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