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guajiro [1.7K]
4 years ago
14

The amount of heat involved in the synthesis of 1 mole of a compound from its elements, with all substances in their standard st

ates at 25°C, is called _____.
A) standard heat of formation


B) heat of solidification


C) enthalpy


D) heat of reaction
Chemistry
2 answers:
Pachacha [2.7K]4 years ago
8 0

Answer:

A

Explanation:

goblinko [34]4 years ago
6 0

Answer:

A) standard heat of formation

Explanation:

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Explanation:

PbBr_{2} will dissociate into ions as follows.

         PbBr_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Br^{-}(aq)

Hence, K_{sp} for this reaction will be as follows.

                   K_{sp} = [Pb^{2+}][Br^{-}]^{2}

We take x as the molar solubility of PbBr_{2} when we dissolve x moles of solution per liter.

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So, equilibrium solubility expression will be as follows.

            K_{sp} = ([Pb^{2+}]_{o} + x)([Br^{-}]_{o} + 2x)^{2}

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            4.67 \times 10^{-6} = x \times (0.10)^{2}

                        x = 4.67 \times 10^{-4} M

Thus, we can conclude that molar solubility of PbBr_{2} is 4.67 \times 10^{-4} M.

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