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2 years ago

If you are administering an insulin dose of 90.0 mg from a bottle at a concentration of 10.0 mg/mL,

Chemistry

1 answer:

Fiesta28 [93]2 years ago

4 0

Answer:

9 mL.

Explanation:

Dosage of insulin is 90 mg

The concentration of insulin is 10 mg/mL

We need to find how many milliliters of the solution do you need to give the patient. It can be calculated as follows :

$x=\dfrac{90\ \text{mg}}{10\dfrac{\text{mg}}{\text{mL}}}\\\\x=\dfrac{9}{1}\ \text{mL}$

So, 9 mL of the solution is to be given to the patient.

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What did Mendel do that made his predictions so accurate

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He worked with large numbers of plants.

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3 years ago

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A certain reaction is exothermic in the forward direction. The reaction has more moles of gas on the product side. Which of the

alexgriva [62]

Answer:

Decreasing the pressure

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3 years ago

With 21 g of Zinc, and 7 g of CuCl2, how much ZnCl2 is made in grams?

mina [271]

Answer: 7.07 grams

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}$

$\text{Moles of} zinc=\frac{21g}{65g/mol}=0.32moles$

$\text{Moles of} CuCl_2=\frac{7g}{134g/mol}=0.052moles$

$Zn+CuCl_2\rightarrow Cu+ZnCl_2$

According to stoichiometry :

1 mole of $CuCl_2$ require 1 mole of $Zn$

Thus 0.052 moles of $CuCl_2$ will require= $\frac{1}{1}\times 0.052=0.052moles$ of $Zn$

Thus $CuCl_2$ is the limiting reagent as it limits the formation of product and $Zn$ is the excess reagent.

As 1 mole of $CuCl_2$ give = 1 mole of $ZnCl_2$

Thus 0.052 moles of $CuCl_2$ give = $\frac{1}{1}\times 0.052=0.052moles$ of $ZnCl_2$

Mass of $ZnCl_2=moles\times {\text {Molar mass}}=0.052moles\times 136g/mol=7.07g$

Thus 7.07 g of $ZnCl_2$ will be produced from the given masses of both reactants.

8 0

2 years ago

What changes happens when you run ?

oksano4ka [1.4K]

Answer:

It increases endurance, builds muscle to maintain an optimal body fat composition, promotes cardiovascular health, strengthens the heart, and even improves your overall mood. Combined with weight training, running can help you maintain the perfect balance of mental stimulation and physical fitness.

Explanation:

4 0

2 years ago

Consider these changes.

Ede4ka [16]

Answer:

(a) The system does work on the surroundings.

(b) The surroundings do work on the system.

(d) No work is done.

Explanation:

The work (W) done in a chemical reaction can be calculated using the following expression:

W = -R.T.Δn(g)

where,

R is the ideal gas constant

T is the absolute temperature

Δn(g) is the difference between the gaseous moles of products and the gaseous moles of reactants

R and T are always positive.

If Δn(g) > 0, W < 0, which means that the system does work on the surroundings.

If Δn(g) < 0, W > 0, which means that the surroundings do work on the system.

If Δn(g) = 0, W = 0, which means that no work is done.

(a) Hg(l) ⇒ Hg(g)

Δn(g) = 1 - 0 = 1. W < 0. The system does work on the surroundings.

(b) 3 O₂(g) ⇒ 2 O₃(g)

Δn(g) = 2 - 3 = -1. W > 0. The surroundings do work on the system.

(c) CuSO₄.5H₂O(s) ⇒ CuSO₄(s) + 5H₅O(g)

Δn(g) = 5 - 0 = 5. W < 0. The system does work on the surroundings.

(d) H₂(g) + F₂(g) ⇒ 2 HF(g)

Δn(g) = 2 - 2 = 0. W = 0. No work is done.

3 0

3 years ago