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alisha [4.7K]
3 years ago
6

Please help, I'm struggling with stoichiometry

Chemistry
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

a) HNO3

b) 26.8g (3 s.f.)

c) 1.29g (3 s.f.)

Please see the attached pictures for full solution.

To balance an equation, ensure that the number of atoms for each element is the same on both sides.

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Which one of the following statements is not true concerning 2.00 L of a 0.100 M solution of Ca3(PO4)2?
Len [333]

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .......(1)

  • <u>For A:</u>

Molarity of calcium phosphate solution = 0.100 M

Volume of solution = 2.00 L

Putting values in equation 1, we get:

0.100M=\frac{\text{Moles of }Ca_3(PO_4)_2}{2.00}\\\\\text{Moles of }Ca_3(PO_4)_2=(0.100mol/L\times 2.00L)=0.200mol

Moles of calcium phosphate = 0.200 moles

  • <u>For B:</u>

1 mole of calcium phosphate contains 3 moles of calcium atoms, 2 moles of phosphate atoms and 8 moles of oxygen atoms.

So, 0.200 moles of calcium phosphate will contain = (8\times 0.200)=1.6 moles of oxygen atoms.

Moles of oxygen atoms = 1.6 moles

  • <u>For C:</u>

Molarity of calcium phosphate solution = 0.100 M

Volume of solution = 1.00 L

Putting values in equation 1, we get:

0.100M=\frac{\text{Moles of }Ca_3(PO_4)_2}{1.00}\\\\\text{Moles of }Ca_3(PO_4)_2=(0.100mol/L\times 1.00L)=0.100mol

Moles of calcium ions = (0.100\times 3)=0.300 moles

  • <u>For D:</u>

Molarity of calcium phosphate solution = 0.100 M

Volume of solution = 5.00 L

Putting values in equation 1, we get:

0.100M=\frac{\text{Moles of }Ca_3(PO_4)_2}{5.00}\\\\\text{Moles of }Ca_3(PO_4)_2=(0.100mol/L\times 5.00L)=0.500mol

Moles of phosphorus atoms = (0.500\times 2)=1.00 moles

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of atoms

Number of phosphorus atoms in 0.500 moles of calcium phosphate will be = (1.00\times 6.022\times 10^{23})=6.022\times 10^{23}

  • <u>For E:</u>

1 mole of calcium phosphate contains 3 moles of calcium ions and 2 moles of phosphate ions.

So, 0.200 moles of calcium phosphate will contain = (3\times 0.200)=0.600 moles of calcium ions

Moles of calcium ions = 0.600 moles

Hence, the correct answer is Option B.

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What procedure did you use to complete the lab?

→Procedures that needs to be considered to complete the lab are- a thorough knowledge of lab assignments, knowledge about safety equipment, reviewing the MSDS of chemicals for lab experiment etc.

<h3>Explanation:</h3>

To be lab prepared one must follow these procedures-

1. One should have the knowledge of lab assignments to make the lab experiment easier.

2. To be aware about safety equipment and their uses in lab, like- the location of fire extinguisher in lab.

3. To know the steps of experiments to be performed

4. To fill notebook of lab with information regarding the experiment

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