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3 years ago

The resistance of the light bulb changed as the voltage (and current) changed. Why does this resistance change occur?

1 answer:

8 0

This resistance current is directly proportional to voltage and inversely proportional to resistance. In other words, as the voltage increases, so does the current. Hope this helps !!

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If a driver is tired, the thinking distance will be less. True or false.why?

Evgesh-ka [11]

Answer:

False

Explanation:

When a driver is impaired the brain will need an extra second or two to wake up, after it does wake up it tends to drift off regularly.

8 0

3 years ago

One particle has a charge of -1.87 x 10-9 C, while another particle has a charge of -1.10 x 10-9 C. If the two particles are sep

bogdanovich [222]

Answer:D 7.41 x 10-6 N

Explanation: AP*X

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2 years ago

An electron initially has a speed 16 km/s along the x-direction and enters an electric field of strength 27 mV/m that points in

weqwewe [10]

Answer:

a) $t=1.4\times 10^{-5}\ s$

b)S= 46.4 cm

Explanation:

Given that

Velocity = 16 Km/s

V= 16,000 m/s

E= 27 mV/m

E=0.027 V/m

d= 22.5 cm

d= 0.225 m

lets time taken by electron is t

d = V x t

0.225 = 16,000 t

$t=1.4\times 10^{-5}\ s$

We know that

F = m a = E q ------------1

Mass of electron ,m

$m=9.1\times 10^{-31}\ kg$

Charge on electron

$q=1.6\times 10^{-19}\ C$

So now by putting the values in equation 1

$a=\dfrac{E q}{m}$

$a=\dfrac{1.6\times 10^{-19}\times 0.027}{9.1\times 10^{-31}}\ m/s^2$

$a=4.74\times 10^{9}\ m/s^2$

$S= ut+\dfrac{1}{2}at^2$

Here initial velocity u= 0 m/s

$S= \dfrac{1}{2}\times 4.74\times 10^{9}\times (1.4\times 10^{-5})^2\ m$

S=0.464 m

S= 46.4 cm

S is the deflection of electron.

4 0

3 years ago

Read 2 more answers

Is charging by contact the same as charging by conduction?

netineya [11]

Answer:So, the difference between charging by induction and conduction comes down to the contact of the neutral object and the object used to charge it. Conduction requires direct contact, while induction does not.

Explanation:

8 0

3 years ago

Read 2 more answers

Two charges, each of 2.9 microC are placed at two corners of a square 50cm on a side, If the charges are on one side of the squa

anyanavicka [17]

Answer:

The magnitude of the electric field and direction of electric field are $146.03\times10^{3}\ N/C$ and 75.36°.