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3 years ago

7

a bag of sugar is found to have the same weight on planet earth as an identical bag of dry sawdust on planet Jupiter explain why

the masses of the two bags must be different

1 answer:

disa [49]3 years ago

4 0

Answer:

Because Jupiter is a much larger planet than Earth, its gravitational pull is 240% stronger than that of earth. This is why sawdust, which is lighter than its equivalent measure of sugar would weigh more on Jupiter.

Explanation:

Let's assume that a type of bag can contain 50 kilograms of sugar. If that same bag was filled up with sawdust instead, it would weigh far less than 50Kg.

If that bag of sawdust, on earth weighed 35Kg for instance, on Jupiter, the new weight would be:

35Kg x 2.4 = 84Kg

Put differently, Jupiter simply has a stronger gravitational pull than earth. This extra pull is attributed to its size.

Cheers

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Consider a product with three components in series, with reliabilities of 0.90, 0.80, and 0.99 for components A, B, and C, r

Feliz [49]

Answer:0.853

Explanation:

Given

Reliability of A is 0.90

Reliability of B is 0.80

Reliability of C is 0.99

B has a backup with reliability of 0.8

i.e. B has a component in parallel to it.

A,B& C is series.

B actual reliability is

$R_b=1-\left ( 1-0.8\right )\left ( 1-0.8\right )$

$R_b=0.96$

Thus $R_{net}$ is given by

$R_{net}=R_A\times R_B\times R_C$

$R_{net}=0.9\times 0.96\times 0.99$

$R_{net}=0.8553$

5 0

3 years ago

7. A car is travelling along a road at 30 ms when a pedestrian steps into the road 55 m ahead. The

trasher [3.6K]

Answer: Car collide with man

Explanation:

Given

Speed of car is $u=30\ m/s$

Distance of the man from the car is $s=55\ m$

Reaction time $t_r=0.5\ s$

Rate of deceleration $a_d=-10\ m/s^2$

Distance traveled in the reaction time $d_o=30\times 0.5=15\ m$

Net effective distance to cover $d=55-15=40\ m$

Distance required to stop the car

$\Rightarrow v^2-30^2=2(-10)(s)\\\Rightarrow 0-900=-20s\\\Rightarrow s=45\ m$

Require distance is more than that of net effective distance. Hence, car collides with the man.

6 0

3 years ago

Suppose that the voltage across the resistor is held constant at 40 volts. If the resistance is steadily decreasing at a rate of

hjlf

Answer:

The current is increasing at a rate of 0.32 ampere per second.

Explanation:

The voltage of the resistor is modelled after Ohm's Law, which states that voltage is directly proportional to current:

$V = i\cdot R$ (1)

Where:

$V$ - Voltage, measured in volts.

$i$ - Current, measured in amperes.

$R$ - Resistance, measured in ohms.

An expression for the rate of change in voltage is found by Differential Calculus:

$\frac{dV}{dt} = \frac{di}{dt}\cdot R +i\cdot \frac{dR}{dt}$

$\frac{dV}{dt} = \frac{di}{dt}\cdot R + \frac{V}{R}\cdot \frac{dR}{dt}$ (2)

Where:

$\frac{dV}{dt}$ - Rate of change in voltage, measured in volts per second.

$\frac{di}{dt}$ - Rate of change in current, measured in amperes per second.

$\frac{dR}{dt}$ - Rate of change in resistance, measured in ohms per second.

If we know that $\frac{dV}{dt} = 0\,\frac{V}{s}$ , $R = 5\,\Omega$ , $V = 40\,\Omega$ and $\frac{dR}{dt} = -0.2\,\frac{\Omega}{s}$ , then the rate of change in current is:

$5\cdot \frac{di}{dt}-1.6 = 0$ (3)

$\frac{di}{dt} = 0.32\,\frac{A}{s}$

The current is increasing at a rate of 0.32 ampere per second.

5 0

3 years ago

The activation energy for the isomerization reaction of CH3NC in Problem 14 is 161 kJ mol 1, and the reaction rate constant at 6

astraxan [27]

Answer:

Explanation:

Below is an attachment containing the solution to the question.

5 0

3 years ago

You place a piece of aluminum at 250.0∘C ∘ C in 9.00 kg k g of liquid water at 20.0∘C ∘ C . None of the water boils, and the fin

Mice21 [21]

Answer:

m₁ = 0.37 kg

Explanation:

According to Law of conservation of energy:

Heat Lost by Aluminum = Heat Gained by Water

m₁C₁ΔT₁ = m₂C₂ΔT₂

where,

m₁ = mass of piece of aluminum = ?

C₁ = specific heat capacity of aluminum = 900 J/kg.°C

ΔT₁ = Change in temperature of aluminum = 250°C - 22°C = 228°C

m₂ = mass of water = 9 kg

C₂ = specific heat capacity of water = 4200 J/kg.°C

ΔT₁ = Change in temperature of aluminum = 22°C - 20°C = 2°C

Therefore,

m₁(900 J/kg.°C)(228 °C) = (9 kg)(4200 J/kg.°C)(2°C)

m₁ = (75600 J)/(205200 J/kg)

<u>m₁ = 0.37 kg</u>

5 0

3 years ago