Answer:
See explanation.
Explanation:
Hello,
In this case, we could have two possible solutions:
A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

That is the mass of copper (II) sulfate contained in 1 mol of substance.
B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

So you can solve for the moles of the solute:

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

But this is just a supposition.
Regards.
Hello,
I'm not very sure but I think the correct answer is D) Water Wave
I really hope this helps!!!! Happy Holidays!!!! (:
Answer:
Atomic radius of sodium = 227 pm
Atomic radius of potassium = 280 pm
Explanation:
Atomic radii trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
Consider the example of sodium and potassium.
Sodium is present above the potassium with in same group i.e, group one.
The atomic number of sodium is 11 and potassium 19.
So potassium will have larger atomic radius as compared to sodium.
Atomic radius of sodium = 227 pm
Atomic radius of potassium = 280 pm
Answer:
In the reaction between p-aminophenol and acetic anhydride to form acetaminophen, 4.5 ml of water were added. This was done to recover the product out the container. Water was used as a means of carrying out the product out the container. However, it should be noted that we would want a small amount to be added in order to avoid the product dissolving onto it.
Explanation:
Answer:



Explanation:
Mass of dog = 



So,



Mass of the dog in the other units is
,
and
.