Answer:
Vibrational Energy Of HCl in the lowest state :
Classical Limit for stretching of HCl bond from its equilibrium length :
Percent of equilibrium Bond Length :
8.58 %
Explanation:
H-Cl bond Length = 0.127 nm =
<u>Frequency </u>from<em> v = </em>0 to <em>v </em>= 1 is 2886
<u>Reduced mass</u>
but this has units in amu , to convert it in Kg divide it by
and 1000(to convert gram itno Kg)
<u>Calculation of Force constant :</u>
Here,
k = force constant
Put the value of frequency , reduced mass and calculate for force constant
Solve the left hand side and square it. Then multiply it with reduced mass
k = 475.97 N/m
Calculation of lowest energy
h = planck's constant =
On solving ,
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Calculation of Stretching of HCl bond:
<em>Use formula :</em>
here Q = stretching bond length
Put , k = 475.97 N/m , and solve for Q
take square root
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Calculation of Percentage extension:
Percentage
Percentage = 8.58 %
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