Answer:
Answer
Answer is option B coz da negative charge r more thn positive
1mol—44g/mol
0.10mol—x
x=0.10*44
x=4.4 g
Answer:
T = 215.33 °C
Explanation:
The activation energy is given by the Arrhenius equation:

<u>Where:</u>
k: is the rate constant
A: is the frequency factor
Ea: is the activation energy
R: is the gas constant = 8.314 J/(K*mol)
T: is the temperature
We have for the uncatalyzed reaction:
Ea₁ = 70 kJ/mol
And for the catalyzed reaction:
Ea₂ = 42 kJ/mol
T₂ = 20 °C = 293 K
The frequency factor A is constant and the initial concentrations are the same.
Since the rate of the uncatalyzed reaction (k₁) is equal to the rate of the catalyzed reaction (k₂), we have:

(1)
By solving equation (1) for T₁ we have:
Therefore, we need to heat the solution at 215.33 °C so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction.
I hope it helps you!
Lead has a higher density
Answer:
Option b. 9.59
Explanation:
First, let us calculate the pH. This is illustrated below:
[H3O+] = 3.9 x 10-5 M
pH = —Log [H3O+]
pH = —Log [3.9 x 10-5]
pH = 4.41
Recall: pH + pOH = 14
4.41 + pOH = 14
Collect like terms
pOH = 14 — 4.41
pOH = 9.59