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2 years ago

Eading and

Chemistry

1 answer:

4vir4ik [10]2 years ago

5 0

Answer: 25.8 g of $Cl_2$ will be produced from the decomposition of 73.4 g of $AuCl_3$

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} AuCl_3=\frac{73.4g}{303g/mol}=0.242moles$

The balanced chemical reaction is:

$2AuCl_3\rightarrow 2Au+3Cl_2$

According to stoichiometry :

2 moles of $AuCl_3$ produce = 3 moles of $Cl_2$

Thus 0.242 moles of will produce= $\frac{3}{2}\times 0.242=0.363mol$ of $Cl_2$

Mass of $Cl_2$ = $moles\times {\text {Molar mass}}=0.363mol\times 71g/mol=25.8g$

Thus 25.8 g of $Cl_2$ will be produced from the decomposition of 73.4 g of $AuCl_3$

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2 years ago

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denpristay [2]

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2 years ago

Read 2 more answers

Match the following metric terms. 1. the basic measure of mass in the metric system meter 2. prefix meaning one-hundredth (.01)

lidiya [134]

Answer: Here's the answer hope this helps

Explanation:

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3 years ago

Could someone help me with this?

Varvara68 [4.7K]

Solving part-1 only

KMnO_4

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Actually it's the oxidation number of Mn

Let's find how?

$\\ \tt\Rrightarrow x+1+4(-2)=0$

$\\ \tt\Rrightarrow x+1-8=0$

$\\ \tt\Rrightarrow x-7=0$

$\\ \tt\Rrightarrow x=+7$

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Purple as per the color of potassium permanganate

$\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}$

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1 year ago

Explain what Happens at the saturation point when adding salt to water at room temperature.

lorasvet [3.4K]

Answer:

See below

Step-by-step explanation:

You won't see much happening. The solution is saturated, so the salt will fall to the bottom of the container and sit there. It will not dissolve.

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The process is

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2 years ago