If I'm not wrong I believe it would be 343 different ways.
We plug in 14 for x when we set the two equations equal to each other to prove they are equal.
So true LM congruent to MN
Answer:
2 13/20
Step-by-step explanation:
12x2-7=6-2x2+2
14x^2-15=0
a=14 , b =0 , c=-15
0^2-4x14x(-15) =
840
Answer:
Brent’s club has more possible team combinations because there are more members to choose from
Step-by-step explanation:
Brents club can be created in C12 6 =12!/6!/6!=7*8*9*10*11*12/(2*3*4*5*6)=
=924 variants
Miguel's club can be created in C10 6=10!/6!/4!=7*8*9*10/(2*3*4)=210 variants
924>210 so Brent’s club has more possible team combinations because there are more members to choose from