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Nastasia [14]
3 years ago
9

When the computer you are working on uses energy it also produces waste energy. What type of energy is this waste energy?

Physics
1 answer:
mihalych1998 [28]3 years ago
5 0
i think it is phisical energy
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An asteroid has acquired a net negative charge of 149 C from being bombarded by the solar wind over the years, and is currently
bearhunter [10]

Answer:

93.125 × 10^(19)

Explanation:

We are told the asteroid has acquired a net negative charge of 149 C.

Thus;

Q = -149 C

charge on electron has a value of:

e = -1.6 × 10^(-19) C

Now, for us to determine the excess electrons on the asteroid, we will just divide the net charge in excess on the asteroid by the charge of a single electron.

Thus;

n = Q/e

n = -149/(-1.6 × 10^(-19))

n = 93.125 × 10^(19)

Thus, it has 93.125 × 10^(19) more electrons than protons

5 0
3 years ago
Consider two soap bubbles with radius r1 and r2 (r1 <r2) connected via a valve. What happens if we open the valve​
Sedaia [141]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

The pressure difference of the first bubble is   \Delta  P _1 =10  J/m^3

The pressure difference of the second bubble is  \Delta  P _2 =20  J/m^3

The pressure difference on the second bubble is higher than that of the first bubble so when the valve is opened pressure from second bubble will cause air to flow toward the first bubble making is bigger

Explanation:

From the question we are told that

    The  radius of the first bubble is  r_1 =  10 \ mm=0.01 \ m

      The radius of the second bubble is  r_2  =  5 \ mm  =  0.005 \ m

      The surface tension of the soap solution is  s =  25 \ mJ/m^2 = 25*10^{-3} J/m^2

Generally according to the Laplace's Law for a spherical membrane the pressure difference is mathematically represented as

         \Delta  P  =  \frac{4 s}{R}

Now the pressure difference for the first bubble is  mathematically evaluated as

        \Delta  P _1 =  \frac{4 s}{r_1}

substituting values  

       \Delta  P _1 =  \frac{4 *25 *10^{-3}}{0.01}

       \Delta  P _1 =10  J/m^3

Now the pressure difference for the second bubble is  mathematically evaluated as

        \Delta  P _2 =  \frac{4 s}{r_1}

       \Delta  P _2 =  \frac{4 *25 *10^{-3}}{0.005}

       \Delta  P _2 =20  J/m^3

3 0
3 years ago
How do fossils provide evidence that evolution has taken place
zzz [600]
<span>Fossils provide solid evidence that organisms from the past are not the same as those found today; they show a progression of evolution. Scientists calculate the age of fossils and categorize them to determine when the organisms lived relative to each other. Hope this helps</span>
7 0
3 years ago
Consider a mass-spring system. The spring has a spring constant 2.17e 3 N/m. On the end is a mass of 4.71 kg. You start at equil
Novosadov [1.4K]

Answer:

7.4 cm

Explanation:

K = 2.17 x 10^3 N/m

m = 4.71 kg

v = 1.78 m/s (It is maximum velocity)

The angular velocity

\omega =\sqrt{\frac{k}{m}}

\omega =\sqrt{\frac{2.71\times 10^{3}}{4.71}}

ω = 24 rad/s

Maximum velocity, v = ω x A

Where, A be the maximum displacement

1.78 = 24 x A

A = 0.074 m = 7.4 cm

8 0
4 years ago
PLEASE HELP !
pochemuha

B

HOPE IT HELPS LET ME KNOW IF U NEED EXPLANATION

4 0
3 years ago
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