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3 years ago

When a moving object collides with an object that isn't moving, what happens to the kinetic energy of each object?

2 answers:

8 0

The kinetic energy of the object being hit will increase and the the potential energy will decrease. The kinetic energy of the object that collided with the other said object will increase and there will be not potential energy. This is my personal knowledge on the matter.

Although the internet states otherwise:

In the extreme case, multiple objects collide, stick together, and remain motionless after the collision. Since the objects are all motionless after the collision, the final kinetic energy is also zero; the loss of kinetic energy is a maximum.

a_sh-v [17]3 years ago

6 0

Answer:

Since the objects are all motionless after the collision, the final kinetic energy is also zero; the loss of kinetic energy is a maximum. Such a collision is said to be perfectly inelastic.

Explanation:

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Which of the following is true concerning hurricanes?

densk [106]

Answer:

Explanation:

B. is correct because every time usually when a hurricane hits it causes flooding causing multiple homes to be ruined. It is a known fact that usually hurricanes start close or in along with tornadoes, the water, meaning once they hit land they have some water to flood that land with.

C. is absolutely false hurricanes have VERY strong wind gusts.

D. is absolutely wrong they do alter landscapes by ripping trees and plants and houses out of the ground making the landscapes look different.

A. is wrong they tend to deposit and remove sediment evenly.

~ LadyBrain

6 0

3 years ago

Read 2 more answers

At a certain instant, the earth, the moon, and a stationary 1160 kg spacecraft lie at the vertices of an equilateral triangle wh

Afina-wow [57]

Answer:

$W = 1.22 \times 10^9 J$

Explanation:

Initial potential energy of the given spacecraft is given as

$U = -\frac{GM_e m}{r} - \frac{GM_m m}{r}$

so we have

$U = - \frac{Gm}{r}(M_e + M_m)$

so we have

$M_e = 5.98 \times 10^{24} kg$

$M_m = 7.35 \times 10^{22} kg$

$m = 1160 kg$

$r = 3.84 \times 10^8 m$

$U = - \frac{(6.67 \times 10^{-11})(1160)}{3.84 \times 10^8}(5.98 \times 10^{24} + 7.35 \times 10^{22})$

$U = -1.22 \times 10^9 J$

now total work done to move it to infinite is given

W = 0 - U

$W = 1.22 \times 10^9 J$

6 0

3 years ago

The Hoover dam is a hydroelectric power plant that converts the energy of falling water into electricity. Which of the following

vlabodo [156]

The correct answer to the question is : B) The weight of the water, and C) The height of the water.

EXPLANATION :

Before coming into any conclusion, first we have to understand potential energy of a body.

The potential energy of a body due to its position from ground is known as gravitational potential energy.

The gravitational potential energy is calculated as -

Potential energy P.E = mgh

Here, m is the mass of the body, and g is the acceleration due to gravity.

h stands for the height of the body from the ground.

We know that weight of a body is equal to the product of mass with acceleration due to gravity.

Hence, weight W = mg

Hence, potential energy is written as P.E = weight × height.

Hence, potential energy depends on the weight and height of the water.

3 0

3 years ago

Read 2 more answers

a volleyball is hit upward with an initial velocity of 7.5 m/s. calculate the displacement of the volleyball when its final velo

Luden [163]

Answer:

The displacement of the volleyball is 2.62 m

Explanation:

Given;

initial velocity of the volleyball, u = 7.5 m/s

final velocity of the volleyball, v = 2.2 m/s

displacement of the volleyball, d = ?

Apply the following kinematic equation;

v² = u² - 2gd

2gd = u² - v²

$d = \frac{u^{2}-v^{2} }{2g}\\\\d = \frac{7.5^{2}-2.2^{2} }{2*9.8}\\\\d = 2.62 \ m$

Therefore, the displacement of the volleyball is 2.62 m

7 0

3 years ago

Calculate the wavelength of an electron (m = 9.11 × 10-28 g) moving at 3.66 × 106 m/s.

valina [46]

The answer is 1.99 × 10⁻¹⁰ m.

To calculate this we will use De Broglie wavelength formula:
λ = h/(m*v)
λ - the wavelength
h - Plank's constant: h = 6.626 × 10⁻³⁴ Js
v - speed
m - mass

It is given:
λ = ?
m = 9.11 × 10⁻²⁸ g
v = 3.66 × 10⁶ m/s

After replacing in the formula:
λ = h/(m*v) = 6.626 × 10⁻³⁴ /(9.11 × 10⁻²⁸ * 3.66 × 10⁶) = 1.99 × 10⁻¹⁰ m

6 0

3 years ago

Read 2 more answers