Answer:
In space we feel weightlessness because the earth's gravity has less effect on us. The Earth's gravitational attraction at those altitudes is only about 11% less than it is at the Earth's surface. If you had a ladder that could reach as high as the shuttle's orbit, your weight would be 11% less at the top.
Explanation:
Hope this helps:)
Based on internet sources, <span>the basic formulas are: v^2/r = (at)^2/r = a ==> at^2 = r ==> t = sqrt(r/a).
</span>
<span>Assuming the missing units are mutually compatible, as in the following example, they don't need to be known. </span>
<span>Acceleration = 1.6 cramwells/s^2 </span>
<span>Radius = 150 cramwells </span>
<span>t = sqrt(150/1.6) = 9.68 s.
I hope this helps.</span>
Answer:
Atoms of tellurium (Te) have the greatest average number of neutrons equal to 76.
Explanation:
In the periodic table, Elements are represented with their respected symbols. Above the symbol is the elements atomic number which is equal to the number of protons in each atom. Below the symbol is the mass number of that element which is roughly equal to the sum of neutrons and protons of that atom.
To calculate the number of neutrons we can take the difference of Atomic number and mass number:
Number of neutrons = mass number - atomic number
<u>- Tin:</u>
Atomic number = 50
Mass number = 119
Number of neutrons = mass number - atomic number = 119 - 50
Number of neutrons = 69
<u>- Antimony(Sb):</u>
Atomic number = 51
Mass number = 122
Number of neutrons = mass number - atomic number = 122 - 51
Number of neutrons = 71
<u>- Tellurium(Te):</u>
Atomic number = 52
Mass number = 128
Number of neutrons = mass number - atomic number = 128 - 52
Number of neutrons = <u>76</u>
<u>- Iodine(I):</u>
Atomic number = 53
Mass number = 127
Number of neutrons = mass number - atomic number = 127 - 53
Number of neutrons = 74
Here, the greatest number of neutrons is for the atoms of Tellurium(Te).
Answer: The field lines bend away from the second positive charge
Explanation: opposite attracts, same repulse
<span>The 2nd truck was overloaded with a load of 16833 kg instead of the permissible load of 8000 kg.
The key here is the conservation of momentum.
For the first truck, the momentum is
0(5100 + 4300)
The second truck has a starting momentum of
60(5100 + x)
And finally, after the collision, the momentum of the whole system is
42(5100 + 4300 + 5100 + x)
So let's set the equations for before and after the collision equal to each other.
0(5100 + 4300) + 60(5100 + x) = 42(5100 + 4300 + 5100 + x)
And solve for x, first by adding the constant terms
0(5100 + 4300) + 60(5100 + x) = 42(14500 + x)
Getting rid of the zero term
60(5100 + x) = 42(14500 + x)
Distribute the 60 and the 42.
60*5100 + 60x = 42*14500 + 42x
306000 + 60x = 609000 + 42x
Subtract 42x from both sides
306000 + 18x = 609000
Subtract 306000 from both sides
18x = 303000
And divide both sides by 18
x = 16833.33
So we have the 2nd truck with a load of 16833.33 kg, which is well over it's maximum permissible load of 8000 kg. Let's verify the results by plugging that mass into the before and after collision momentums.
60(5100 + 16833.33) = 60(21933.33) = 1316000
42(5100 + 4300 + 5100 + 16833.33) = 42(31333.33) = 1316000
They match. The 2nd truck was definitely over loaded.</span>
