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o-na [289]
2 years ago
11

The sodium content of twenty 300-gram boxes of organic cornflakes was determined. The data (in milligrams) are as follows: 131.1

5, 130.69, 130.91, 129.54, 129.64, 128.77, 130.72, 128.33, 128.24, 129.65, 130.14, 129.29, 128.71, 129.00, 129.39, 130.42, 129.53, 130.12, 129.78, 130.92 In this question, we want to verify whether the true mean sodium content of this brand of cornflakes differs from 130 milligrams under the significance level, a = 0.05.
Chemistry
1 answer:
Elena L [17]2 years ago
6 0

Answer:

The content of the brand actually differs from the expected average with the specified significance.

Explanation:

Hello,

By considering the given data, the average is computed via the addition of all the data divided by the sample's size:

m_{Na}=\frac{sum(m_i)}{20}

m_{Na}=\frac{2594.94mg}{20} =129.747mg

Now, that result, based on the significance, is compared with the following result:

130-0.05=129.95mg

Since the computed average is less than the previous result containing the significance, one states that the content of the brand actually differs from the expected average with the specified significance.

Best regards.

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Answer:
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pOH = 12.362

Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
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Substitute in the above equation to get the pH as follows:
pH = -log[0.023]
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2- getting the pOH:
We know that:
pH + pOH = 14
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Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
pOH = 14 - 1.638
pOH = 12.362

Hope this helps :)
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