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o-na [289]
3 years ago
11

The sodium content of twenty 300-gram boxes of organic cornflakes was determined. The data (in milligrams) are as follows: 131.1

5, 130.69, 130.91, 129.54, 129.64, 128.77, 130.72, 128.33, 128.24, 129.65, 130.14, 129.29, 128.71, 129.00, 129.39, 130.42, 129.53, 130.12, 129.78, 130.92 In this question, we want to verify whether the true mean sodium content of this brand of cornflakes differs from 130 milligrams under the significance level, a = 0.05.
Chemistry
1 answer:
Elena L [17]3 years ago
6 0

Answer:

The content of the brand actually differs from the expected average with the specified significance.

Explanation:

Hello,

By considering the given data, the average is computed via the addition of all the data divided by the sample's size:

m_{Na}=\frac{sum(m_i)}{20}

m_{Na}=\frac{2594.94mg}{20} =129.747mg

Now, that result, based on the significance, is compared with the following result:

130-0.05=129.95mg

Since the computed average is less than the previous result containing the significance, one states that the content of the brand actually differs from the expected average with the specified significance.

Best regards.

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The change in pH is calculated by:

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moles NH4+ = moles NH3 = 0.100 L x 0.100 M = 0.0100 
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NH3 + H+ = NH4+ 
moles NH3 = 0.0100 - 0.000300=0.00970 
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the change is  = 9.26 - 9.23 =0.03 

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The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a b
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Answer:

The answer is "\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}"

Explanation:

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CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\

 In this, the CH_3COOH is a weak acid so, it not completely dissociated.

CH_3COONa \ (aq) \ \ and \ NaCl were strong electrolytes they are completely dissociated.

The HCl is a strong acid so, it is completely dissociated So, the net ionic equation is:

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Consider the reaction. mc014-1.jpg How many grams of methane should be burned in an excess of oxygen at STP to obtain 5.6 L of c
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The reaction for the combustion of methane can be expressed as follows.
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