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o-na [289]
2 years ago
11

The sodium content of twenty 300-gram boxes of organic cornflakes was determined. The data (in milligrams) are as follows: 131.1

5, 130.69, 130.91, 129.54, 129.64, 128.77, 130.72, 128.33, 128.24, 129.65, 130.14, 129.29, 128.71, 129.00, 129.39, 130.42, 129.53, 130.12, 129.78, 130.92 In this question, we want to verify whether the true mean sodium content of this brand of cornflakes differs from 130 milligrams under the significance level, a = 0.05.
Chemistry
1 answer:
Elena L [17]2 years ago
6 0

Answer:

The content of the brand actually differs from the expected average with the specified significance.

Explanation:

Hello,

By considering the given data, the average is computed via the addition of all the data divided by the sample's size:

m_{Na}=\frac{sum(m_i)}{20}

m_{Na}=\frac{2594.94mg}{20} =129.747mg

Now, that result, based on the significance, is compared with the following result:

130-0.05=129.95mg

Since the computed average is less than the previous result containing the significance, one states that the content of the brand actually differs from the expected average with the specified significance.

Best regards.

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A mixture of methane and carbon dioxide gases contains methane at a partial pressure of 431 mm Hg and carbon dioxide at a
KatRina [158]

Answer:

XCH₄ = 0.461

XCO₂ = 0.539

Explanation:

Step 1: Given data

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  • Partial pressure of carbon dioxide (pCO₂): 504 mmHg

Step 2: Calculate the total pressure in the container

We will sum both partial pressures.

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P = 431 mmHg + 504 mmHg = 935 mmHg

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Xi = pi / P

XCH₄ = pCH₄/P = 431 mmHg/935 mmHg = 0.461

XCO₂ = pCO₂/P = 504 mmHg/935 mmHg = 0.539

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Answer:

Explanation:

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The  volume  that    0.878  mol  occupy  at   the  same   temperature  and  pressure   is  calculated  as follows


if   0.274  mol  occupy  6.62 L  what  about  0.878  mol

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