274 mL H3 O+ and fully neutralized
It will take one teaspoon of Mg(OH)2 to completely neutralize 2.00×10^2mL of H3O+.
<h3>What is the purpose of milk of magnesia?</h3>
- For a brief period of time, this medicine is used to relieve sporadic constipation.
- It is an osmotic laxative, which means that it works by drawing water into the intestines, which aids in causing bowel movement.
<h3>What dosage of milk of magnesia is recommended for constipation?</h3>
- Take Milk of Magnesia once day, preferably before bed, in divided doses, or as prescribed by a physician.
- suggested dosage: 30 mL to 60 mL for adults and kids 12 years of age and older. 15 mL to 30 mL for children aged 6 to 11 years.
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the question you are looking for is
People often take milk of magnesia to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 teaspoon, which contains 4.00x 10^{2} mg of Mg(OH)_2. What volume of an HCl solution with a pH of 1.3 can be neutralized by one dose of milk of magnesia? If the stomach contains 2.00x10^{2}mL of pH 1.3 solution, is all the acid neutralized? If not, what fraction is neutralized?
Explanation:
a) Using Beer-Lambert's law :
Formula used :
where,
A = absorbance of solution = 0.945
c = concentration of solution = ?
l = length of the cell = 1.20 cm
= molar absorptivity of this solution =
(
)
14.16 μM is the molarity of the red dye solution at the optimal wavelength 519nm and absorbance value 0.945.
b) 
1 L of solution contains 
moles of red dye.
Mass of moles of red dye:
c) In order to dilute red dye solution by 5 times, we will need to add 1 L of water to solution of given concentration.
Concentration of red dye solution = 
Concentration of red solution after dilution = c'
The final concentration of the diluted solution is 
<span>NH3 is the answer, if u look up its ph its a weak base</span>
Given data: <span>molar mass = 180.2 g/mol in 920.0 ml of water at 25 °c.
</span><span>the vapor pressure of pure water at 25 °c is 23.76 mm hg.
</span>Asked: <span>the vapor pressure of a solution made by dissolving 109 grams of glucose
</span><span>
Solution:
moles glucose = 109 g/ 180.2 g/mol=0.605
mass water = 920 mL x 1 g/mL = 920 g
moles water = 920 g/ 18.02 g/mol=51.1
mole fraction water = 51.1 / 51.1 + 0.605 =0.988
vapor pressure solution = 0.988 x 23.76 = 23.47 mm Hg</span>
