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3 years ago

Cheap microscopes often produce images that have colored edges. Why?

Physics

1 answer:

sleet_krkn [62]3 years ago

7 0

Answer:

Because of the lens

Explanation:

The lens have a problem and it's the same that the atmosphere offers, if you look at the moon in the night while a cloud is close (it looks better on full moon) you can see an aura wrapping the moon, that happens because the clouds in the atmosphere divide the light and make that aura. The same happens with the lens of some microscopes, that's why the most expensive microscopes are avoiding the use of lens.

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El índice es la tabla de contenidos de un documento. El desarrollo es el cuerpo de información contenida en un documento

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3 years ago

A wheel of radius 30 cm is rotating at a rate of 2.0 revolutions every 0.080 s. (A) through what angle, in radians, does the whe

Alchen [17]

A)
2revs in 0.08s
so in 1s thats 25revs
therefore thats 50π radians in one second

b)
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3 years ago

High-frequency sound waves have a shorter (amplitude, pitch, wavelength) and a higher (amplitude, pitch, wavelength) than low-fr

I am Lyosha [343]

The most appropriate answers are ...

high frequency sound has shorter wavelength !

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4 years ago

Read 2 more answers

A microscope has an eyepiece with a 1.8 cm focal length and a 0.8 cm focal length objective lens. Assuming a relaxed eye, calcul

igomit [66]

Answer:

$0.848\ \text{cm}$

$232.66$

Explanation:

N = Near point of eye = 25 cm

$f_o$ = Focal length of objective = 0.8 cm

$f_e$ = Focal length of eyepiece = 1.8 cm

l = Distance between the lenses = 16 cm

Object distance is given by

$v_o=l-f_e\\\Rightarrow v_o=16-1.8\\\Rightarrow v_o=14.2\ \text{cm}$

$u_o$ = Object distance for objective

From lens equation we have

$\dfrac{1}{f_o}=\dfrac{1}{u_o}+\dfrac{1}{v_o}\\\Rightarrow u_o=\dfrac{f_ov_o}{v_o-f_o}\\\Rightarrow u_o=\dfrac{0.8\times 14.2}{14.2-0.8}\\\Rightarrow u_o=0.848\ \text{cm}$

The position of the object is $0.848\ \text{cm}$ .

Magnification of eyepiece is

$M_e=\dfrac{N}{f_e}\\\Rightarrow M_e=\dfrac{25}{1.8}\\\Rightarrow M_e=13.89$

Magnification of objective is

$M_o=\dfrac{v_o}{u_o}\\\Rightarrow M_o=\dfrac{14.2}{0.848}\\\Rightarrow M_o=16.75$

Total magnification is given by

$m=M_eM_o\\\Rightarrow m=13.89\times 16.75\\\Rightarrow m=232.66$

The total magnification is $232.66$ .

3 0

3 years ago

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taurus [48]

Answer:

Right coronary artery

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3 years ago

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