1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
k0ka [10]
3 years ago
8

What are three factors that move the blood back to the heart

Physics
1 answer:
Kazeer [188]3 years ago
3 0
The arteries move blood away from the heart so therefore, the veins retract the blood throughout the body which eventually goes back to the heart and repeats itself nonstop
You might be interested in
On a spinning ride at the fair, it is inertia that keeps you moving in a circle. true or false​
lions [1.4K]

False, the inertia does not keep us moving in a circle on a spinning ride at the fair.

Answer: Option B

<u>Explanation: </u>

Inertia is the resisting force of any object which resists in change in their state. If an object is moving the inertia will act in opposing direction to the force acting on the object stopping its motion.

Similarly, if an object resembles at rest, then the inertia will be acting against the force tending to move that stationary object. So, on a spinning ride at fair, when a person sits there, the inertia acting on the person will prevent the person to falling down from the fair and not in moving in a circle.

6 0
3 years ago
Who was the carthaginian general who used elephants to cross the alps in the second punic war
goldfiish [28.3K]
<span>the answer is Hannibal</span>
3 0
3 years ago
Read 2 more answers
When a parachutist jumps from an airplane, he eventually reaches a constant speed, called the terminal speed. Once he has reache
Masteriza [31]

Answer:

b) True.    the force of air drag on him is equal to his weight.

Explanation:

Let us propose the solution of the problem in order to analyze the given statements.

The problem must be solved with Newton's second law.

When he jumps off the plane

     fr - w = ma

Where the friction force has some form of type.

     fr = G v + H v²

Let's replace

     (G v + H v²) - mg = m dv / dt

We can see that the friction force increases as the speed increases

At the equilibrium point

      fr - w = 0

      fr = mg

      (G v + H v2) = mg

For low speeds the quadratic depended is not important, so we can reduce the equation to

     G v = mg

     v = mg / G

This is the terminal speed.

Now let's analyze the claims

a) False is g between the friction force constant

b) True.

c) False. It is equal to the weight

d) False. In the terminal speed the acceleration is zero

e) False. The friction force is equal to the weight

3 0
3 years ago
A 1400 kg car is traveling east on the highway at 31 m/s and collides into the rear of a slower moving pickup truck of 2400 kg,
zloy xaker [14]

Answer: 31 m/s due east

Explanation: this question can be solved using the law of conservation of linear momentum.

This law states that in a closed or isolated system, during collision, the vector sum of momentum before collision equals the vector sum of momentum after collision.

Momentum = mass × velocity

From our question, our parameters before collision are given below as

Mass of car = mc = 1400kg

Speed of car =vc = 31 m/s (due east)

Mass of truck = mt = 2400kg

Velocity of truck = vt = 25 m/s ( due east )

After collision

Velocity of car = ?

Velocity of truck = 34 m/s ( due east )

Vector sum of momentum before collision is given as

1400 (31) + 2400 (25) = 43400 + 60000 = 103400 kgm/s

After collision the truck is seen to move faster (v = 34 m/s) which implies that the car also moves due east .

1400 (v) + 2400(25) .... A positive value is between both momenta because they are in the same direction.

After collision, we have that

1400v + 60000

Vector sum of momentum before collision = vector sum of momentum after collision

103400 = 1400v + 60000

103400 - 60000 = 1400v

43400 = 1400v

v = 43400/ 1400

v = 31 m/s due east

4 0
3 years ago
Show the weight of the ladder and draw the missing Frictional force.
madreJ [45]
Since there is no friction between the ladder and the wall, there can be no vertical force component. That's the tricky part ;)

So to find the weight, divide the 100N <em>normal</em> force by earths gravitational acceleration, 9.8m/s^2

W =  \frac{N}{g}  =  \frac{100N}{9.8m/s^{2}} =  \frac{100}{9.8} = 10.2kg


Then;
Draw an arrow at the base of the ladder pointing towards the wall with a value of 30N, to show the frictional force.
5 0
2 years ago
Other questions:
  • Classify each possible hypothesis about a medicinal aloe vera plant as falsifiable or non-falsifiable.
    13·1 answer
  • Which of the following statements about matter is true? Mass and matter are always the same. Matter is made up of atoms and has
    15·1 answer
  • A person on a roof throws one ball downward and an identical ball upward at the same speed. The ball thrown downward hits the gr
    7·1 answer
  • According to Wien's Law, how many times hotter is an object whose blackbody emission spectrum peaks in the blue, at a wave lengt
    8·1 answer
  • What is 1.0 x 10^9 in standard form?
    9·1 answer
  • Calculate the weight of a 1 kg mass at earth's surface. The mass of the of the Earth's surface if the mass of the earth is 6 x 1
    7·1 answer
  • WILL GIVE BRAINLIEST HELP FASTWhat is the mass of Planet X? Note: The constant of universal gravity (G) equals 6.674 X 10-11 N·m
    11·1 answer
  • Are cells made of tisse?
    14·2 answers
  • What is the difference in graph shape when it is postion vs.time vs. velocity vs. time graph. Using a motion detector.
    6·1 answer
  • In your words, describe how you think life as a human might be different on a world orbiting around a dying star. Think about th
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!