The range of the projectile is 188 m
Explanation:
The motion of the arrow in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
The path of a projectile is the combination of these two motions: see figure in attachment.
In order to find the horizontal range of the projectile, we just need to calculate the horizontal distance travelled.
We have:
t = 5.0 s (time of fligth of the projectile)
and the horizontal velocity is constant, and it is given by

where
is the initial velocity
is the angle of projection
Substituting,

And therefore, the range of the projectile is:

Learn more about projectile motion:
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Answer:
The second one, the higher the hertz the higher the frequency we hear
Explanation:
Answer:
D: X: Low potential energy
Y: High potential energy
Z: Flow of electrons
Explanation: trust
Answer:
-2.33 m/s²
Explanation:
The computation of the skateboarder’s acceleration is shown below;
Acceleration means the change in velocity per unit with respect to time.
In the given case, the initial velocity is 7 m/s.
As in the question it is mentioned that it comes to a stop, so the final velocity would be zero.
And, The time elapsed is 3 seconds.
Now the following equation should be used
a = (v,final - v,initial) ÷ t
= (0 - 7)/3
= -2.33 m/s²
I think the amplitude changed