1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
emmainna [20.7K]
3 years ago
13

A river has a steady speed of 0.480 m/s. a student swims upstream a distance of 1.00 km and swims back to the starting point. (a

) if the student can swim at a speed of 1.40 m/s in still water, how long does the trip take?
Physics
1 answer:
gregori [183]3 years ago
4 0

Steady speed of river = 0.480 m/s

Swimming speed of student in still water = 1.40 m/s  

When the student is swimming upstream the  velocity he is going up = 1.40-0.48= 0.92 m/s

When the student is swimming downstream the  velocity he is going down = 1.40+0.48= 1.88 m/s

Time taken to travel upstream = \frac{1000}{0.92} =1087 seconds = 18.12 minutes

Time taken to travel downstream = \frac{1000}{1.88} =592 seconds = 8.87 minutes

Total time taken = 18.12+8.87 = 26.99 minutes

You might be interested in
A 0.30-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. After a 0.20 s collision, the ob
andre [41]

Answer:

I = -2.1 kg.m/s

Explanation:

Given,

mass of the object,m = 0.30 Kg

initial speed, v_i = 3 m/s

time of collision = 0.20 s

final speed, v_f = -4 m/s

Impulse = change in momentum

I = m (v_f-v_i)

I = 0.30\times (-4-3)

I = -2.1 kg.m/s

Hence, impulse of the object is equal to I = -2.1 kg.m/s

5 0
3 years ago
What is the SI unit for moment​
natali 33 [55]

Answer:

Newton Metre

Explanation:

8 0
3 years ago
Three equal point charges, each with charge 1.15 μCμC , are placed at the vertices of an equilateral triangle whose sides are of
julsineya [31]

Answer:

U=50.96J

Explanation:

The electrostatic potential energy for pair of charge is given by

U=1/4π∈₀×(q₁q₂/r)

Hence for a system of three charges the electrostatic potential energy can be found by adding up the potential energy for all possible pairs or charges.For three equal charges on the corners of an equilateral triangle,the electrostatic potential energy is given by:

U=1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)

U=3×1/4π∈₀×(q²/r)

Substitute given values

So

U=3\frac{1}{4\pi E_{o} }\frac{q^{2} }{r}\\  U=3\frac{1}{4\pi8.85*10^{-12} }\frac{(1.15*10^{-6}C )^{2} }{0.0007m}\\  U=50.96J

8 0
3 years ago
The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.320 with the floor. If
mart [117]

Answer:  29.50 m

Explanation: In order to calculate the higher accelation to stop a train  without moving the crates inside the wagon which is traveling at constat speed we have to use the second Newton law so that:

f=μ*N the friction force is equal to coefficient of static friction  multiply the normal force (m*g).

f=m.a=μ*N= m*a= μ*m*g= m*a

then

a=μ*g=0.32*9.8m/s^2= 3.14 m/s^2

With this value we can determine the short distance to stop the train

as follows:

x= vo*t- (a/2)* t^2

Vf=0= vo-a*t then t=vo/a

Finally; x=vo*vo/a-a/2*(vo/a)^2=vo^2/2a= (49*1000/3600)^2/(2*3.14)=29.50 m

5 0
3 years ago
An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see
siniylev [52]

Answer:

3.88 * 10^(-15) J

Explanation:

We know that the Potential energy of the electron at the beginning of its motion is equal to the Kinetic energy at the end of its motion, when it reaches the plates.

First, we get the potential and potential energy:

Electric potential = E * r

E = electric field

r = distance between plates

Potential = 2.2 * 10^6 * 0.011

= 2.42 * 10^4 V

The relationship between electric potential and potential energy is:

P. E. = q*V

q = charge of electron = 1.602 * 10^(-19) C

P. E. = 2.42 * 10^4 * 1.602 * 10^(-19)

P. E. = 3.88 * 10^(-15) J

6 0
3 years ago
Other questions:
  • Which theory proposed by Galileo is considered a “big mistake of his life”? What did the theory state, and why was it a “big mis
    5·2 answers
  • An 8.00-kg point mass and a 12.0-kg point mass are held in place 50.0 cm apart. A particle of mass m is released from a point be
    15·1 answer
  • Which statement best describes metallic bonding?
    10·2 answers
  • Consider a spherical Gaussian surface and three charges: q1 = 1.60 μC , q2 = -2.61 μC , and q3 = 3.67 μC . Find the electric flu
    13·1 answer
  • What is the thermal energy of an object
    9·2 answers
  • Calculate the density of a rod of metal in g/cm3, with a mass of 9.58g, a diameter of 8 mm and a height of 3.5cm
    7·1 answer
  • The moon sun is directly overhead at the equator during ( a solstice or an equinox)?.
    9·1 answer
  • What are two roles of bacteria in a nitrogen cycle
    12·2 answers
  • I am lonely to death
    11·2 answers
  • Help me with this please
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!