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Kryger [21]
3 years ago
6

How many bonding and non-bonding electron pairs are found in the BF3 molecule?​

Chemistry
1 answer:
Contact [7]3 years ago
8 0

Answer:

MARK AS BRAINLIEST

Explanation:

Boron trifluoride only has six valence electrons and is one of the relatively rare second period covalent molecules that disobeys the octet rule. There are three bonded groups and so no lone pairs. Six electrons implies three electron pairs and therefore a trigonal geometry.

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What kind of orbital is occupied by the lone pair electrons in caffeine molecule?
Nataly [62]
The middle nitrogen has two sigma bonds and one pi bond. You know that one p orbital is used in the double bond and two sp2 orbitals are involved in the sigma bond. This leaves one sp2 orbital for the lone pair to occupy.
8 0
3 years ago
Solve the radical equation. what is the extraneous solution to the radical equation? the solution -1 is an extraneous solution.
Arada [10]

Answer:

X = 7

Explanation:

4 0
2 years ago
A 24.81g sample of a gaseous compound containing only oxygen,and chlorine is determined to contain 3.01g carbon, 4.00g oxygen an
irinina [24]

Answer:

hi

Explanation:

3 0
3 years ago
Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife​
yuradex [85]

Answer:

\boxed{\text{2408 min}}

Explanation:

The integrated rate law for radioactive decay is

\ln\dfrac{N_{0}}{N_{t}} = kt

1. Calculate the decay constant

\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}

8 0
3 years ago
PLEASE ANSWER THIS QUESTION FAST :(
kramer
Mol sulfuric acid = 19 g * (1 mol) / (98.1 g) = 0.19367 mol
mol H2O = 0.19367 mol H2SO4 * (2 H2O) / (1 H2SO4)
                = 0.387359 mol H2O
grams H2O = 0.387359 mol H2O * (18 g)/(1 mol)
                     = 6.97 g
The answer is 7.0 grams of water
6 0
3 years ago
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