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2 years ago

How many bonding and non-bonding electron pairs are found in the BF3 molecule?

Chemistry

1 answer:

Contact [7]2 years ago

8 0

Answer:

MARK AS BRAINLIEST

Explanation:

Boron trifluoride only has six valence electrons and is one of the relatively rare second period covalent molecules that disobeys the octet rule. There are three bonded groups and so no lone pairs. Six electrons implies three electron pairs and therefore a trigonal geometry.

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You wish to prepare a tape-casting slip containing 50 vol% Al2O3 and 50 vol% polyvinyl butyral (PVB) binder. If the density of A

belka [17]

Answer: The mass of PVB required to produce 1000 grams of tape is 213.4 grams

Explanation:

To calculate the mass of aluminium oxide, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$ .......(1)

For $Al_2O_3$

We are given:

50% (v/v) of $Al_2O_3$

This means that 50 mL of aluminium oxide is present in 100 mL of tape

Calculating the mass of aluminium oxide by using equation 1:

Density of aluminium oxide = $3.98 g/cm^3$

Volume of aluminium oxide = $50mL=50cm^3$ (Conversion factor: $1mL=1cm^3$ )

Putting values in equation 1, we get:

$3.98g/cm^3=\frac{\text{Mass of aluminium oxide}}{50cm^3}\\\\\text{Mass of aluminium oxide}=(3.98g/cm^3\times 50cm^3)=199g$

Mass of aluminium oxide = 199 g

For PVB:

We are given:

50% (v/v) of PVB

This means that 50 mL of PVB is present in 100 mL of tape

Calculating the mass of PVB by using equation 1:

Density of PVB = $1.08 g/cm^3$

Volume of PVB = $50mL=50cm^3$

Putting values in equation 1, we get:

$1.08g/cm^3=\frac{\text{Mass of PVB}}{50cm^3}\\\\\text{Mass of PVB}=(1.08g/cm^3\times 50cm^3)=54g$

Mass of PVB = 54 g

Mass of tape = Mass of aluminium oxide + mass of PVB

Mass of tape = [199 + 54] g = 253 g

To calculate the mass of PVB required to produce 1000 g of tape, we use unitary method:

When 253 grams of tape is made, the mass of PVB required is 54 g

So, when 1000 grams of tape is made, the mass of PVB required will be = $\frac{54}{253}\times 1000=213.4g$

Hence, the mass of PVB required to produce 1000 grams of tape is 213.4 grams

4 0

2 years ago

Two samples of potassium iodide are decomposed into their constituent elements. The first sample produced 13.0 g of potassium an

Cerrena [4.2K]

Answer:

79.4 kg

Explanation:

The formula for potassium iodide is:-

$KI$

This means that they are present in the same mole ration, i.e. 1 : 1

Also for 2 samples, the ratio of the masses must be equal .

So,

$\frac{Mass\ of\ potassium\ in\ sample\ 1}{Mass\ of\ Iodine\ in\ sample\ 1}=\frac{Mass\ of\ potassium\ in\ sample\ 2}{Mass\ of\ Iodine\ in\ sample\ 2}$

Thus,

Mass of potassium in sample 1 = 13.0 g

Mass of Iodine in sample 1 = 42.3 g

Mass of potassium in sample 2 = 24.4 kg

Applying in the above formula, we get that:-

$\frac{13.0\ g}{42.3\ g}=\frac{24.4\ kg}{Mass\ of\ Iodine\ in\ sample\ 2}$

Mass of iodine in sample 2 = 79.4 kg

5 0

3 years ago

What are some interesting facts about magnesium, lead, phosphorus and magnesium nitrate?

Ray Of Light [21]

Lead can be extremely poisonous and was once used in many many paints but caused several deaths from lead poisoning so that was a biggie...
At the center of every chlorophyll molecule, in every plant, there is a magnesium ion. Magnesium is one of the two dozen or so elements that are required for life.

7 0

2 years ago

You have a balloon filled with hellum that has a volume of 4.91 cubic decimeters

juin [17]

Answer:

Explanation:

because the number of heliem is your aswer

5 0

2 years ago

Read 2 more answers

Selenium (Se) has 30 protons and 20 neutrons in each atom, therefore its atomic

allochka39001 [22]

Answer:

30, 50

Explanation:

Hello,

In this since an element's atomic number is equal to the number of protons in its atom, we can infer that selenium's atomic number is 30. Moreover, due to the fact the the neutrons are equal to the atomic mass minus the atomic number or the number of protons, by knowing the number of neutrons we compute the atomic as follows:

$neutrons=mass-protons\\\\mass=neutrons+protons\\\\mass=30+20\\\\mass=50a.m.u$

Thus, answer is 30, 50.

Best regards.

8 0

3 years ago

How many bonding and non-bonding electron pairs are found in the BF3 molecule?​

How many bonding and non-bonding electron pairs are found in the BF3 molecule?