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Assoli18 [71]
3 years ago
12

How is energy transferred whenhitting a nail?​

Physics
1 answer:
Juli2301 [7.4K]3 years ago
7 0

Answer:

kinetic energy

kinetic energy

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Which equations represent the relationship between wavelength and frequency for a sound wave? Check all that apply. V = f = vf f
Vikentia [17]

It's really hard to make out the gibberish at the end, where the list of choices should be.

Here are the three equations for the relationships among the wavelength, frequency, and wave-speed, for ANY wave:

-- Speed = (wavelength) x (frequency)

-- Wavelength = (Speed) / (frequency)

-- Frequency = (Speed) / (wavelength)

Notice that you only have to remember any ONE of these.  Then you can always get the other ones by multiplying or dividing both sides by the same quantity.

If you want to remember all of them, here are the short forms:

V  =  L · f

L = V / f

f = V / L

6 0
3 years ago
Read 2 more answers
Consider a system of a cliff diver and the earth. the gravitational potential energy of the system decreases by 28,000 j as the
olga2289 [7]

The decrease in gravitational potential energy of the system is given by

\Delta U = (mg) \Delta h

where

m is the mass, g is the gravitational acceleration, and \Delta h is the variation of height of the system.


(mg) also corresponds to the weight of the diver, therefore if we rearrange the equation and we use \Delta U=28000 J and \Delta h=32.0 m, we can find her weight:

mg=\frac{\Delta U}{\Delta h}=\frac{28000 J}{32 m}=875 N

5 0
3 years ago
A relatively small impact crater 20 kilometers in diameter could be made by a comet 2 kilometers in diameter traveling at 25 km/
nadya68 [22]

Answer:

KE=1.3\times 10^{21}\ J

KE=3.1\times 10^{5}\ E

Explanation:

(a)

Given:

  • mass of comet, m=4.2\times 10^{12}\ kg
  • velocity of the comet, v=2.5\times 10^4\ m.s^{-1}

<u>Now, the kinetic energy of the comet can be given by:</u>

KE=\frac{1}{2} m.v^2

KE=0.5\times 4.2\times 10^{12}\times (2.5\times 10^4)^2

KE=1.3\times 10^{21}\ J

(b)

Given:

  • energy released by 1 megaton of TNT, E=4.2\times 10^{15}\ J

<u>Now the kinetic energy of the comet in terms of energy of 1 megaton TNT:</u>

KE=\frac{1.3\times 10^{21}}{4.2\times 10^{15}} E

i.e.

KE=3.1\times 10^{5}\ E

4 0
3 years ago
An 97 kg climber climbs to the top of Mount Everest, which has a peak height of 8850 m above sea level. What is the climber’s po
Kisachek [45]
Eg=mgh
Eg=(97)(9.8)(8850)
Eg=8412810J
4 0
3 years ago
Need Help !
Bad White [126]

Answer: 5.96m/s

Explanation:

Given the following :

Mass of car (m) = 1500kg

Velocity (V) = 5.25m/s

Forward force of engine = 1250N

Diatance moved = 4.8m

Final Velocity =?

Final kinetic energy = Initial kinetic energy + work done by engine

Initial kinetic energy = 0.5 × mass × velocity^2

Initial kinetic energy = 0.5 × 1500 × 5.25^2

Initial kinetic energy = 20671.875 J

Work done by engine = Force × distance

Work done by engine = 1250 × 4.8 = 6000J

Final kinetic energy = (20671.875 + 6000) J

= 26671.875 J

From kinetic energy = 0.5mv^2

26671.875 = 1/2 × 1500 × v^2

53343.75 = 1500v^2

v^2 = 35.5625

v = sqrt(35.5625)

v = 5.96m/s

3 0
3 years ago
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