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Answer: Earth's orbital path around the Sun</h2><h2>
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The <u>Ecliptic</u> refers to the orbit of the Earth around the Sun. Therefore, <u>for an observer on Earth it will be the apparent path of the Sun in the sky during the year, with respect to the "immobile background" of the other stars.</u>
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It should be noted that the ecliptic plane (which is the same orbital plane of the Earth in its translation movement) is tilted with respect to the equator of the planet about 
approximately. This is due to the inclination of the Earth's axis.
Hence, the correct option is Earth's orbital path around the Sun.
Answer:
2.43J
Explanation:
Given parameters:
Mass of the arrow = 0.155kg
Velocity = 31.4m /s
Unknown:
Kinetic energy when it leaves the bow = ?
Solution:
The kinetic energy of a body is the energy in motion of the body;
it can be derived using the expression below:
K.E = 
m v²
m is the mass
v is the velocity
Solve for K.E;
K.E = x 0.155 x 31.4 = 2.43J
If it helps Mark Brainliest.. :)
natural magnetism of the Earth derives from its iron core. This not only provides a useful direction finder for compasses, but actually protects life on Earth by deflecting charged particles in space. The "magnetosphere" is a large region that surrounds the Earth as it moves in its orbit around the Sun. It consists of charged ions that are prevented from directly striking the surface, where they could injure living organisms and harm the environment.When solar eruptions on the Sun increase the flow of charged particles, industries such as power transmission and communication can be still be affected despite the magnetic field
Answer:
447 K
Explanation:
25 C = 25 + 273 = 298 K
Assuming ideal gas, we can apply the ideal gas law
Since pressure is tripled, then 
. Volume is halved, then 
2,450 Joules, kinetic energy is 1/2 mass x velocity squared.
