Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
i will answer -- justv please clarify ur question
ig its 8.7 tho ?
Step-by-step explanation:
Answer:
the answer is 8, the distance between -11 and -3 is 8
Step-by-step explanation:
if you count the between the numbers it's a total of 8
Answer:
The two sides we know are O pposite (300) and A djacent (400).
SOHCAH TOA tells us we must use T angent.
Calculate Opposite/Adjacent = 300/400 = 0.75
Find the angle from your calculator using tan-1
:)
Answer:
x - 4y = 8
Step-by-step explanation:
Since the Point-Slope Formula is already given to you, convert it to Slope-Intercept Form, and you do that by doing this:
y - 1 = ¼(x - 12) >> y - 1 = ¼x - 3
y - 1 = ¼x - 3
+ 1 + 1
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y = ¼x - 2 >> Slope-Intercept Form
After doing this, you are ready to convert to Standard Form, and you do that by doing this:
y = ¼x - 2
-¼x -¼x
-----------
-¼x + y = -2
Now unfortunately, we do not want fractions as our coefficients, so the way to eliminate the fraction is to multiply the equation by the Multiplicative Inverse of -¼, which is -4:
-4[-¼x + y = -2] >> x - 4y = 8 → New equation without fractions
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