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Chemistry

1 answer:

Ivahew [28]2 years ago

8 0

Answer:

Exothermic Reaction

Explanation:

Its a combustion reaction and they are always exothermic in nature.

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Which of the following mixtures may be act as a buffer solution?

lions [1.4K]

Answer:

B) HF, NaF

Explanation:

A buffer solution is made up of a weak acid and its conjugate base.
In this case, HF is a weak acid and NaF is the conjugate base, therefore the mixture of HF, and NaF would make a perfect buffer solution.
The buffer would have the weak acid HF and its conjugate base, F- which comes from the soluble salt NaF.

4 0

3 years ago

How is it possible for there to be more than one kind of atom of the same element?

tiny-mole [99]

They are called isotopes.

Isotopes have the same number of electrons and protons in their unionized state. They differ in the number of neutrons. The first and simplest example is hydrogen.

The most common hydrogen has

1 proton

1 electron and

0 neutrons

It has 2 cousins

1 proton

1 electron

1 neutron

And

1 proton

1 electron

2 neutrons.

Most elements have some differences in the number of neutrons present in their nuclei. Cesium and Xenon have the most number of isotopes. Each has 36. You wonder how the atoms are held together.

6 0

2 years ago

Read 2 more answers

1 C8H10(l) +21/2O2(g) → 8CO2(g) + 5H2O(g), Hcomb= ? Hf for C8H10(l) = +49.0kJ/mol C8H10(l) Use the balanced combustion reaction

nikklg [1K]

Answer:

$H_{comb}=-4406kJ/mol$

Explanation:

Hello,

In this case, the enthalpy of combustion is understood as the energy released when one mole of fuel, in this case octene, is burned in the presence of oxygen and is computed with the enthalpies of formation of the fuel, carbon dioxide and water as shown below (oxygen is circumvented as it is a pure element):

$H_{comb}=8*\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{10}}$

Thus, since we already know the enthalpy of combustion of the fuel, for carbon and water we have -393.5 and -241.8 kJ/mol respectively, thereby, the enthalpy of combustion turns out:

$H_{comb}=8*(-393.5kJ/mol)+5(-241.8kJ/mol)-49.0kJ/mol\\\\H_{comb}=-4406kJ/mol$