1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Georgia [21]
3 years ago
8

A person steps off the end of a 3.45 � high diving board and drops to the water below. (a) How long does it take for the person

to reach the water? (b) What is person’s speed on entering the water? (c) What is person’s speed on entering the water if they step off a 12.0 � diving
Physics
1 answer:
777dan777 [17]3 years ago
6 0

Answer:

(a) 0.84 s

(b) 8.22 m/s

(c) 15.33 m/s

Explanation:

u = 0 , h = 3.45 m, g = 9.8 m/s^2

Let time taken to reach the water is t and the velocity at the time of hitting of water surface is v.

(a) Use first equation of motion

s = u t + 1/2 a t^2

3.45 = 0 + 0.5 x 9.8 x t^2

t = 0.84 second

(b) Use first equation of motion

v = u + a t

v = 0 + 9.8 x 0.84 = 8.22 m/s

(c) If h = 12 m

use third equation of motion

v^2 = u^2 + 2 g h

v^2 = 0 + 2 x 9.8 x 12

v = 15.33 m / s

You might be interested in
A musical note has a frequency of 512 Hz. If the wavelength of the note is 0.685 m, what is the speed of the sound of that note?
riadik2000 [5.3K]

Answer:

350.72 m/s

Explanation:

Formula for velocity of wave is;

v = fλ

Where;

v is speed

f is frequency

λ is wavelength

We are given;

f = 512 Hz

λ = 0.685 m

Thus;

v = 512 × 0.685

v = 350.72 m/s

5 0
2 years ago
What did the asymptote say to the removable discontinuity worksheet answers?
ra1l [238]

“Don't hand that holier than thou line to me” is what the asymptote said to the removable discontinuity.

 

 

The distance between the curve and the line where it approaches zero as they tend to infinity is the line in the asymptote of a curve. This is unusual for modern authors but in some sources the requirement that the curve may not cross the line infinitely often is included.

 

The point that does not fit the rest of the graph or is undefined is called a removable discontinuity. By filling in a single point, the removable discontinuity can be made connected.

6 0
3 years ago
A 600g toy train completes 10 laps of its circular track in 1 min 20s. If the radius of the track is 1.2 m, Find the centripetal
Lynna [10]

Wow !  This will take more than one step, and we'll need to be careful
not to trip over our shoe laces while we're stepping through the problem.

The centripetal acceleration of any object moving in a circle is

                          (speed-squared)  /  (radius of the circle)  .

Notice that we won't need to use the mass of the train.

We know the radius of the track.  We don't know the trains speed yet,
but we do have enough information to figure it out.  That's what we
need to do first.

Speed  =  (distance traveled) / (time to travel the distance).

Distance = 10 laps of the track.   Well how far is that ? ? ?

1 lap = circumference of the track = (2π) x (radius) =  2.4π  meters

10 laps =  24π  meters.

Time = 1 minute 20 seconds  =  80 seconds

The trains speed is  (distance) / (time)

                               =  (24π meters) / (80 seconds)

                               =        0.3 π  meters/second .

NOW ... finally, we're ready to find the centripetal acceleration.

                                 <span> (speed)²  /  (radius)

                           =    (0.3π m/s)²  /  (1.2 meters)

                           =    (0.09π m²/s²)  /  (1.2 meters)

                           =    (0.09π  /  1.2)   m/s²

                           =          0.236  m/s²  .        (rounded)

If there's another part of the problem that wants you to find
the centripetal FORCE ...

Well,       Force = (mass) · (acceleration) .

We know the mass, and we ( I ) just figured out the acceleration,
so you'll have no trouble calculating the centripetal force.       </span>
4 0
2 years ago
The velocity time graph of a car shown below a) Calculate the magnitude of displacement of the car in 40 seconds. b) During whic
Gekata [30.6K]

Answer:

a) 0 metres

b) From time 0 s to 10 s , the car was accelerated. Its velocity accelerated from 0m/s to 20 m/s

c) 20 m/s

Explanation:

a) <em>Formula of displacement= velocity x time</em>

time=40 s

velocity =0 m/s

∴ displacement= 0 x 40 = 0 m

Magnitude of displacement is 0 m

b) The increase in velocity shows that there has been acceleration.

c) The average velocity of the car is =\frac{0+40}{2\\}   {initial velocity + final velocity}

                                                            =\frac{40}{2}

                                                             =20

Therefore, the magnitude of the average velocity  of the car is 20 m/s

3 0
3 years ago
1. A negatively charged rod is moved near the top of a positively charged electroscope. What
Xelga [282]

Answer:

A) Moves closer together

7 0
3 years ago
Other questions:
  • Which of the following people would make the best scientist?
    14·2 answers
  • Why would scientists call solids and liquids a condensed phase of matter?
    8·1 answer
  • A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm un
    15·1 answer
  • an aeroplane taking off from a field has a run of 500m. What is the acceleration and take off velocity if it leaves the ground 1
    6·1 answer
  • Which of the following is not a vector
    14·2 answers
  • What’s the answer ???
    15·1 answer
  • How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?
    5·1 answer
  • Which of the following statements does NOT describe force?
    10·2 answers
  • What are the units for specific charge?<br> A. C/kg<br> B. C*kg<br> C. kg/C<br> D. 1/C*kg
    15·1 answer
  • when a branding iron gets heated in a fire the handle becomes hot, how is the energy transferred to the handle
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!