Answer:
Southern state and local elections in 1876 differed from those in previous years in that the election of 1876 was one of the closest races in American history. It tested the Constitution and resulted in a compromise that ended Reconstruction in America.
The election of 1876 between Rutherford B. Hayes and Democrat Samuel Tilden of New York was one of the most hostile, controversial campaigns in American history. The vote was 8-7 along party lines to award the disputed electoral college votes to Hayes, making him the winner.
Explanation:
The Compromise of 1876 is known for being the catalyst for the end of Reconstruction era, it was one of the most contentious and controversial presidential elections in American history.
Republican nominee Rutherford B. Hayes faced Democrat Samuel J. Tilden. After a controversial post-election process, He lost the popular vote to Democrat Samuel J. Tilden but he won an intensely disputed electoral college vote after a Congressional commission awarded him twenty contested electoral votes Hayes was declared the winner. The Hayes-Tilden Compromise is often seen as the final point that brought an end to Reconstruction, as it led to the removal of the US army from the South.
As Florida's Supreme Court had earlier declared a Democratic victory in the 1876 gubernatorial election, Democrats had been restored to power all across the South. The Compromise of 1876 effectively ended the Reconstruction era.
Southern Democrats' promised to protect civil and political rights of blacks as they were not kept, and to end of federal interference in southern affairs. This led to widespread disenfranchisement of blacks voters. Other factors that contributed to the end of Reconstruction were the Panic of 1873 and political corruption in the United States.
The Compromise of 1877 (the Great Betrayal) was an informal, unwritten deal, that settled the intensely disputed 1876 U.S. presidential election. It resulted in the United States federal government pulling the last troops out of the South, and formally ended the Reconstruction Era.
Here if we assume that there is no air friction on both balls then we can say
![F = mg](https://tex.z-dn.net/?f=F%20%3D%20mg)
now the acceleration is given as
![F = ma = mg](https://tex.z-dn.net/?f=F%20%3D%20ma%20%3D%20mg)
![a = g](https://tex.z-dn.net/?f=a%20%3D%20g)
so here both the balls will have same acceleration irrespective of size and mass
so we can say that to find out the time of fall of ball we can use
![y = \frac{1}{2}gt^2](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
![t = \sqrt{\frac{2y}{g}}](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cfrac%7B2y%7D%7Bg%7D%7D)
now from above equation we can say that time taken to hit the ground will be same for both balls and it is irrespective of its mass and size
Answer:
160 years.
Explanation:
From the question given above, the following data were obtained:
Initial count rate (Cᵢ) = 400 count/min
Half-life (t½) = 40 years
Final count rate (Cբ) = 25 count/min
Time (t) =?
Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:
Initial count rate (Cᵢ) = 400 count/min
Final count rate (Cբ) = 25 count/min
Number of half-lives (n) =?
Cբ = 1/2ⁿ × Cᵢ
25 = 1/2ⁿ × 400
Cross multiply
25 × 2ⁿ = 400
Divide both side by 25
2ⁿ = 400/25
2ⁿ = 16
Express 16 in index form with 2 as the base
2ⁿ = 2⁴
n = 4
Thus, 4 half-lives has elapsed.
Finally, we shall determine the time taken for the radioactive material to decay to the rate of 25 counts per minute. This can be obtained as follow:
Half-life (t½) = 40 years
Number of half-lives (n) = 4
Time (t) =?
n = t / t½
4 = t / 40
Cross multiply
t = 4 × 40
t = 160 years.
Thus, it will take 160 years for the radioactive material to decay to the rate of 25 counts per minute.
Answer: 6.9x 107 in standard form is 69,000,000