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Dvinal [7]
3 years ago
15

Pls answer BOTH of these

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
6 0

Answer:

#1 i think is 2x7 i dont know #2 sry

Step-by-step explanation:

Alex17521 [72]3 years ago
4 0
1 is 2/7 i think!!! !!
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What will be the result if the y-intercept of the line shown is changed to an 8,
nataly862011 [7]

I’m on the same question rn and I need help.

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Everyone out there stop moaning around!! Move on with your lives!! Stop posting nonsense boo-hoo c.ra.p on this!! Talk to a ther
Daniel [21]

Answer: This should be under the subject English or Art, not math.

Step-by-step explanation: Go motivation, if a little rude.

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3 years ago
Read 2 more answers
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
If 8x + y = -1 is a true equation, what would be the value of y + 8x
Alexeev081 [22]
That would also be equal to -1
8 0
1 year ago
Question 5 Multiple Choice Worth 1 points)
lara [203]
  • Its key to copying a specified line is to open your beacon to the length of both the section, then use that amount of entrance to label off another section of the same length.
  • To bisect a segment or angle means to divide it into confocal scanning parts. A line segment's bisector would then pass thru the midpoint of its segment.
  • Once copying a segment as well as bisecting a section, its Draw a ray including one end-point step will be the same.
  • So if copying a line and bisecting a line segment, this same needle of both the compass is placed mostly on-line segment's end.
  • Therefore, the "Draw a ray with one endpoint" choices are correct, and the other choices were incorrect.

Learn more:

brainly.com/question/1581615

7 0
2 years ago
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