All categories

3 years ago

Please transform the polar equation to an equation in rectangular coordinates.

1 answer:

4 0

Rcsc(theta) = 3
r/sin(theta) = 3
r =3sin(theta)

Now use the relation between polar coordinates and rectangular coordinates

x = rcos(theta)
y = r sin(theta)

=> x = [3sin(theta)]cos(theta)
x = 3 sin(theta)cos(theta)

and y = [3sin(theta)]sin(theta)
y = 3 [sin(theta)]^2

You might be interested in

answer this if you want 70 pts who ever answers first I will brainliest and give 5 stars with a thank you and you will earn 70 p

vivado [14]

Just use a calculator, the answer is 442

3 0

2 years ago

Choose the correct simplification of x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4t

Umnica [9.8K]

Answer:

<h3>The option A) $x^{10}z^7$ is correct answer.</h3><h3>The correct simplification for the given expression $\frac{x^{12}\times z^{11}}{x^2\times z^4}$ is $x^{10}z^7$ </h3>

Step-by-step explanation:

Given expression is x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power.

The given expression can be written as $\frac{x^{12}\times z^{11}}{x^2\times z^4}$

<h3>To choose the correct simplification of the given expression :</h3>

Now we have to simplify the given expression as below

$\frac{x^{12}\times z^{11}}{x^2\times z^4}$

$=x^{12}\times z^{11}(x^{-2}\times z^{-4})$ ( by using the identity $\frac{1}{a^m}=a^{-m}$ )

$=(x^{12}.x^{-2})\times (z^{11}.z^{-4})$

$=x^{12-2}\times z^{11-4}$ ( by using the identity $a^m.a^n=a^{m+n}$ )

$=x^{10}\times z^7$

$=x^{10}z^7$

∴ $\frac{x^{12}\times z^{11}}{x^2\times z^4}=x^{10}z^7$

<h3>The correct simplification for the given expression $\frac{x^{12}\times z^{11}}{x^2\times z^4}$ is $x^{10}z^7$ </h3><h3>Hence option A) $x^{10}z^7$ is correct answer.</h3>

4 0

3 years ago

What is the output when the input is 0

Cloud [144]

Answer:

When the inputs are 1 and 0, the output is zero.

7 0

3 years ago

Can someone please help me

BigorU [14]

So J is jelly beans and T is trail mix :)
so J= $3.50
T= $1.50

7 0

2 years ago

Zach has a terrarium with the dimensions of 20 by 8 and the terrarium was filled with 3 inches of sand.Zach gets a new terrarium

Vladimir79 [104]

Answer: the sand in the new terrarium is 2 inches deep.

Step-by-step explanation:

Zach has a terrarium with the dimensions of 20 by 8 and the terrarium was filled with 3 inches of sand. It means that the volume of sand that this terrarium contains is

20 × 8 × 3 = 480 inches³

Zach gets a new terrarium that is larger with the dimensions of 10 by 24. If Zach moved the existing sand in the new terrarium and the height of the sand is represented by h, then the volume of sand into he new terrarium is

10 × 24 × h = 240h

Since the volume of sand in both terrariums is equal, then

240h = 480

h = 480/240

h = 2 inches

7 0

2 years ago