Answer:
See attached picture.
Explanation:
Hello,
In this case, starting by 1-butanol, we can make it react with hydrogen bromide (1st step) in order to yield 1-bromobutane. Next, the formed alkyl halide is treated magnesium in the presence of an ether in order to yield butyl magnesium bromide which is a Grignard reagent (2nd step). Finally, by adding carbon dioxide, water and extra hydrogen chloride, a carbonyl group can be formed between two butyl radicals in order to form the 5-nonanone (3rd step) as shown on the attached picture.
Best regards.
Answer:
<em>The capillary tube was too close to the bottom of the beaker.</em>
<em>The ruler may have moved.</em>
<em>Water got into the capillary tube.</em>
<em>The temperature was not allowed to equilibrate in the 2-4 minutes.</em>
Explanation: i did the assignment, & these are the things that it wanted you to list. have a blessed day! :)
Answer: Ionic Bond
Explanation: The electrostatic attraction that binds oppositely charged ions together. alloy. a mixture composed of two or more elements, at least one of which is a metal.
Hope this helped!
Answer: -
15.55 M
35.325 molal
Explanation: -
Let the volume of the solution be 1000 mL.
Density of nitric acid = 1.42 g/ mL
Total Mass of nitric acid Solution = Volume of nitric acid x Density of nitric acid
= 1000 mL x 1.42 g/ mL
= 1420 g.
Percentage of HNO₃ = 69%
Amount of HNO₃ = ![\frac{69} {100} x 1420 g](https://tex.z-dn.net/?f=%20%5Cfrac%7B69%7D%20%7B100%7D%20x%201420%20g%20)
= 979.8 g
Molar mass of HNO₃ = 1 x 1 + 14 x 1 + 16 x 3 = 63 g /mol
Number of moles of HNO₃ = ![\frac{979.8 g}{63 g/ mol}](https://tex.z-dn.net/?f=%20%5Cfrac%7B979.8%20g%7D%7B63%20g%2F%20mol%7D%20%20)
= 15.55 mol
Molarity is defined as number of moles per 1000 mL
We had taken 1000 mL as volume and found it to contain 15.55 moles.
Molarity of HNO₃ = 15.55 M
Mass of water = Total mass of nitric acid solution - mass of nitric acid
= 1420 - 979.8
= 440.2 g
So we see that 440.2 g of water contains 15.55 moles of HNO₃
Molality is defined as number of moles of HNO₃ present per 1000 g of water.
Molality of HNO₃ = ![\frac{15.55 x 1000}{440.2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B15.55%20x%201000%7D%7B440.2%7D%20%20)
= 35.325 molal
Explanation:
taste sour (vinegar)
smell frequently burns nose
texture sticky